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Anton [14]
3 years ago
6

Consider a triangle formed by connecting the three points: (0 0 0), (1 0 0), (1 1 1). a. Find the vector which is perpendicular

to the surface of this triangle, AND has a positive z-direction?
Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

=k−j   or (0 -1 1)

Step-by-step explanation:

The Vector or Outer Product two vectors, say →x&→y, is  

denoted by →x×→y, is a perpendicular vector to the plane containing them.

The given pts. A (0 0 0), B (1 0 0), C (1 1 1) lie in a

plane ABC.

As suchType equation here., the vectors (→(AB ) )and (→AC ) are members, ∈ of the plane ABC

That is □(→(AB )×(→AC))  to the plane ABC

(→(AB ) )=(1-0,0-0,0-0)=(1,0,0)

(→(AC ) )=(1-0,1-0,1-0)=(1,1,1)

(→(AB )×(→AC=  (0i -j  k)

=k−j  

Which is in the positive Z direction

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Put the bolded ones all together and use the union, ∪, symbol to connect them, since something on the graph could be in any piece.

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