1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
By difference of two squares :
X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2
(X+2)=0 therefore x= -2
2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
X^2 - 2x = 0
X(X-2) = 0
X= 0, X= 2
Rewrite the equation below in standard form.
-3x+6y=12
C. -x+2y=4
if you take each term and divide them by 3 you will get the c
Answer:
Imani
Step-by-step explanation:
It izz wat it izzzz!!!
:)
Answer:
1,000,000
Step-by-step explanation:
addition and maths
Answer: theres no pic?
Step-by-step explanation:
