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3 years ago

Is my answer correct? If not, please tell me the correct answer and explain. Thanks in advance!

Mathematics

1 answer:

Marat540 [252]3 years ago

7 0

Unfortunately, you are incorrect because the answer is D. It makes no sense for him to make profit out of selling nothing, so A,B, and C are wrong, and D is correct because it's the only answer that says he can profit if he sells 100 DVDs.

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Consider the radical equation (3√6-x)+4=-8. Explain why the calculation in Problem 1 does not produce a solution to the equation

murzikaleks [220]

Answer:

See explanation below

Step-by-step explanation:

First we will solve the radical equation (which I guess was problem 1),

Let's start by simplifying it:

$3\sqrt{6-x}+4=-8\\ 3\sqrt{6-x}=-8-4\\ 3\sqrt{6-x}=-12\\\sqrt{6-x}=-4$

Now we will solve the equation by squaring both sides of the equation:

$\sqrt{6-x} =-4\\6-x=-4^{2} \\6-x=16\\-x=16-6\\-x=10\\x=-10$

So the calculation for x was that x = -10

However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

$3\sqrt{6-x} +4= -8\\3\sqrt{6-(-10)} +4=-8\\3\sqrt{16}+4 = -8\\ 3(4)+4 = -8\\12 + 4 = -8$

This happens because when we first squared both sides of the equation in the first part of the problem we missed one value for x (remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

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2 years ago

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serious [3.7K]

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vitfil [10]

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dybincka [34]

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Step-by-step explanation:

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