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mr_godi [17]
3 years ago
7

Please help:

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0

Answer:

\angle 1 =47^o\\\angle 2 = 133^o\\\angle 4 = 133^o

Step-by-step explanation:

Notice that angles <1 and <3  are opposed by the vertex, which makes them of equal measure, therefore, <1 = 47 degrees.

Notice as well that angles <1 and <2 combine into a straight line, therefore, they are supplementary angles whose addition gives 180 degrees then we can find the value of angle <2 via:

\angle 1 + \angle 2 = 180^o\\47^o + \angle 2=180^o\\\angle 2 = 180^o-47^o\\\angle 2 =133^o

And finally, angle <4 is opposite through the vertex to angle <2, and therefore they must have the same measure. So, <4 = 133 degrees.

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Suppose that the function u and w are defined as follows.
mars1129 [50]

That funky circle in the middle is the composition of the function. It asks you to take a function as an input and to yield an output that's another function. It's one of the five function operations, along with adding, subtracting, multiplying, and dividing.

When you compose, you might find the notation w(u(x)) easier to understand. It's saying evaluate u then evaluate w.

For our functions, the compositions are:

u(w(x)) = u(2x²) = -(2x²) - 2 = -2x² - 2

w(u(x)) = w(-x - 2) = 2(-x - 2)² = 2(x² + 4x + 4) = =2x²+ 8x +8

Now we evaluate each composition at 4.

u(w(4)) = -2(4²) - 2 = -2(16) - 2 = -32 -2 = -34

w(u(4)) = -2(2²) +8(2) + 8 = -2(4) + 16 + 8 = -8 + 16 + 8 = 16.

Thus, u(w(4)) = -34 and w(u(4)) = 16.

5 0
3 years ago
Help me, please! For 20 pts
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Step-by-step explanation:

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Two cars left the city for a suburb, 120 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the
Virty [35]

Answer:

V1 = 60 km/h

V2 = 40 Km/h

Step-by-step explanation:

The speed of an object is defined as

Speed =  distance / time

Let

V1 be the speed of the faster car

V2 be the speed of the other car

t1 the time it took for the first car to arrive

t2 the time it took for the second car to arrive

d1 the distance traveled by first car

d2 the distance traveled by second car

We know thanks to the problem that

V1 = V2 + 20 Km/h

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