That funky circle in the middle is the composition of the function. It asks you to take a function as an input and to yield an output that's another function. It's one of the five function operations, along with adding, subtracting, multiplying, and dividing.
When you compose, you might find the notation w(u(x)) easier to understand. It's saying evaluate u then evaluate w.
For our functions, the compositions are:
u(w(x)) = u(2x²) = -(2x²) - 2 = -2x² - 2
w(u(x)) = w(-x - 2) = 2(-x - 2)² = 2(x² + 4x + 4) = =2x²+ 8x +8
Now we evaluate each composition at 4.
u(w(4)) = -2(4²) - 2 = -2(16) - 2 = -32 -2 = -34
w(u(4)) = -2(2²) +8(2) + 8 = -2(4) + 16 + 8 = -8 + 16 + 8 = 16.
Thus, u(w(4)) = -34 and w(u(4)) = 16.
Answer:
First box ⇒ 3.6 x 10^-1
Second box ⇒ 3.1 x 10^6
Third box ⇒ 5.3 x 10^-6
Fourth box ⇒ 4.2 x 10^-1
Step-by-step explanation:
I used a calculator and solved it :)
What are the values to choose from?
Answer:
V1 = 60 km/h
V2 = 40 Km/h
Step-by-step explanation:
The speed of an object is defined as
Speed = distance / time
Let
V1 be the speed of the faster car
V2 be the speed of the other car
t1 the time it took for the first car to arrive
t2 the time it took for the second car to arrive
d1 the distance traveled by first car
d2 the distance traveled by second car
We know thanks to the problem that
V1 = V2 + 20 Km/h
t1 = t2 - 1 hour
d1 = d2 = 120 Km
d1 = V1 * t1
d2 = V2* t2
V1 * t1 = V2* t2
V1* t1 = (V1 -20)*(t1 +1)
The system of equations
(V1 -20)*(t1 +1) = 120
V1 * t1 = 120
120 + (120/t1) -20*t1 = 140
(120/t1) -20*t1 = 20
Which gives,
t1 = 2
This means
V1 = 60 km/h
V2 = V1 - 20 Km/h = 40 Km/h