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3 years ago

Solve the system of linear equations by graphing. Round the solution to the nearest tenth as needed.

2 answers:

4 0

Y + 2.3 = 0.45x
y = 0.45x - 2.3

-2y = 4.2x - 7.8
-2(0.45x - 2.3) = 4.2x - 7.8
-0.90x + 4.6 = 4.2x - 7.8
-0.90x - 4.2x = -7.8 - 4.6
-5.1x = - 12.4
x = -12.4 / -5.1
x = 2.4

y + 2.3 = 0.45x
y = 0.45(2.4) - 2.3
y = 1.08 - 2.3
y = -1.2

solution is : (2.4, - 1.2)

earnstyle [38]3 years ago

3 0

y + 2.3 = 0.45x

y = 0.45x - 2.3

-2y = 4.2x - 7.8

-2(0.45x - 2.3) = 4.2x - 7.8

-0.90x + 4.6 = 4.2x - 7.8

-0.90x - 4.2x = -7.8 - 4.6

-5.1x = - 12.4

x = -12.4 / -5.1

x = 2.4

y + 2.3 = 0.45x

y = 0.45(2.4) - 2.3

y = 1.08 - 2.3

y = -1.2

solution is : (2.4, - 1.2)

Unfortunately, I can't do it on a graph here, but I will do it algebraically.

The solution on the graph will be the point of intersection of the two lines representing the equations.

y + 2.3 = 0.45x . . . . . (1)

-2y = 4.2x - 7.8 . . . . . (2)

From (2), y = 3.9 - 2.1x

substituting for y in (1), we have:

3.9 - 2.1x + 2.3 = 0.45x

2.55x = 6.2

x = 6.2/2.55 = 2.4

y = 3.9 - 2.1(2.4) = 3.9 - 5.04 = -1.2

Therefore, solution is (2.4, -1.2)

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3 years ago

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2 years ago

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Please help thank you.

MA_775_DIABLO [31]

Question 1:

To start off this question, we can tell that this is a square because it has 4 right angles and 4 congruent sides.

A square has four parallel sides and 4 congruent sides, so a square is a rhombus and parallelogram.

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A square has 4 sides, so it's also a quadrilateral.

The first choice is your answer.

Question 2:

Not all quadrilaterals are rectangles, so A is incorrect.

Not all quadrilaterals are squares, so B is incorrect.

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Not all quadrilaterals are parallelograms, so D is incorrect.

Thus, C is your answer.

Question 3:

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7 0

3 years ago

Consider the function f(x)= (x+4)(x-2) what is the equation of the axis of symmetry

almond37 [142]

if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

$\bf 0 = (x+4)(x-2)\implies \begin{cases} 0=x+4\implies &-4=x\\ 0=x-2\implies &2=x \end{cases}$

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.

well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys

-4------------(-1)------------2

so the vertex is at x=-1, namely the axis of symmetry is x = -1.

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3 years ago