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IrinaK [193]
3 years ago
14

-3.09 +x= -0.7 What is the answer?​

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
7 0
1. move the constant (x) to the other side
x= -0.7 + 3.09
2. calculate the sum
x=2.39
scZoUnD [109]3 years ago
5 0

Answer:

2.39

Step-by-step explanation:

-3.09+X=-0.7

X=-0.7+3.09

X=2.39

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Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

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Answer with Step-by-step explanation:

We are given that v_1,v_2,..,v_4 are in R^4 and v_1,v_2,v_3 is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

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3 years ago
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