Answer:
dV/dt = 155.74 ft^3/minute
Step-by-step explanation:
Volume V = Area × thickness
Area A= πr ^2
Thickness = 0.2 ft
Volume V = 0.2A = 0.2πr^2
V = 0.2πr^2
Differentiating both sides;
dV/dt = 0.2π × 2r dr/dt = 0.4πr.dr/dt
Given;
r = 400 ft
dr/dt = 0.31 ft/minute
π = 3.14
Substituting the values
dV/dt = 0.4πr.dr/dt = 0.4 × 3.14 × 400 × 0.31
dV/dt = 155.74 ft^3/minute
Answer:
37
Step-by-step explanation: IM MAKING A GUESS IF ITS WRONG IM SORRY I TIRED
Answer:
1/4(8+m)
Step-by-step explanation:
this is your answer for sure
You can do this in parts.
g(-3) = 3(-3) + 1 = -9 + 1 = -8
So, 5g(-3) = 5(-8) = -40.
So f(-1) + 5g(-3) = 2 - 40 = -38
Or you can do this as one big chunk.
f(-1) + 5g(-3)
![=[(-1)^2+1] + 5[3(-3) + 1] \\ = (2) + 5(-9 + 1) \\ = 2 + 5(-8) \\ = 2 - 40 \\ = -38](https://tex.z-dn.net/?f=%3D%5B%28-1%29%5E2%2B1%5D%20%2B%205%5B3%28-3%29%20%2B%201%5D%20%5C%5C%0A%3D%20%282%29%20%2B%205%28-9%20%2B%201%29%20%5C%5C%0A%3D%202%20%2B%205%28-8%29%20%5C%5C%0A%3D%202%20-%2040%20%5C%5C%20%3D%20-38)
