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3 years ago

Why did the music teacher need a ladder

Mathematics

2 answers:

irakobra [83]3 years ago

7 0

Where is the rest of the question ?

qaws [65]3 years ago

5 0

To reach the high notes lol

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What is the degree of 7x^5+6x^3+4x+2

11111nata11111 [884]

The degree is the largest exponent on the variable.

Degree: 5

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3 years ago

What is the simplified form of V 100x35 ?

ElenaW [278]

Answer:

answer is 3500.

answer is 3500

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3 years ago

Hello everyone, I was wondering if you guys could please go subscribe to my youtub/e, and stay subscribed. You don’t have too, b

Greeley [361]

Oh okay I will have a good day

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2 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

2 years ago

Read 2 more answers

Which inequality describes the graph?

irinina [24]

Answer:

y ≥ 3x +4

Step-by-step explanation:

The line is solid, so the inequality will include the "or equal to" case. The shading is above the line, so values of y greater than or equal to those on the line are in the solution set. The only choice with the correct (≥) inequality symbol is ...

y ≥ 3x +4

8 0

2 years ago