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Alexxandr [17]
2 years ago
11

how many 5 digit numbers can be formed using all the digits 1, 2, 3, 4, and 5, such that the number is odd and greater than 4000

0?
Mathematics
1 answer:
stira [4]2 years ago
4 0

Answer:

25

Step-by-step explanation:

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7 x 28<br> = 7(20 + 8<br> = (7 x 20)+(7<br> = 140 + 56<br> = 196
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Vladimir79 [104]

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