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4 years ago

When you divide a number by 1 2 , the result is

Mathematics

2 answers:

Len [333]4 years ago

6 0

A number $n$ divided by 12 is simply $\frac{n}{12}$ .

Lorico [155]4 years ago

3 0

Twice the original number

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How do I solve this

m_a_m_a [10]

U ask someone who can read ur paper it's kinda blurry

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3 years ago

I'd really appreciate if anyone helped! :)

dlinn [17]

In order for the data set to represent a function, there can be no duplicates of the first value.

A. 1 is used as the first value more than once it is NOT a function

B. 3 is used as the first value more than once it is NOT a function

C. no first number is used more than once it IS a function

D. 3 is used as the first value more than once it is NOT a function

Answer: C

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3 years ago

Mr.Changs class has 28 students 4/7 of whom are girls. Which equation shows how to determine the number of girls in Mr. Chang’s

irinina [24]

I think 7 of them are girls and the rest are boys and how i got this answer is I took the 28 and divided it by 4 and got 7.

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3 years ago

Use the identity below to complete the tasks:

quester [9]

Answer:

$a=[2q^{2}r]$

$b=[3s^{2}t]$

Step-by-step explanation:

we have

$8q^{6}r^{3}+27s^{6}t^{3}$

we know that

$8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}$

$27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}$

therefore

$a=[2q^{2}r]$

$b=[3s^{2}t]$

substitute

$a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])$

7 0

3 years ago

Read 2 more answers

What are the attributes of a parallelogram

aleksley [76]

Answer:

simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers