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kirza4 [7]
3 years ago
12

3(x + 1) = -2 (x - 1) -4

Mathematics
2 answers:
AlekseyPX3 years ago
7 0

Answer:

x = -1

Step-by-step explanation:

use distribution

3x + 3 = -2x + 2 - 4

simplify

3x + 3 = -2x - 2

combine like terms

3x + 3 = -2x - 2

-3x                -3x

3 = -5x - 2

+2         +2

5 = -5x

/-5     /-5

-1 = x

Masja [62]3 years ago
5 0

Answer:

x = -2.2

x = -2 if rounded

Step-by-step explanation:

use distribution

3x + 3 = -2x + 2 - 4

simplify

3x + 3 = -2x - 2

combine like terms

3x + 3 = -2x - 2

-3x                -3x

3 = -5x - 2

+2         +2

5 = -5x

/-5     /-5

-1 = x

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inessss [21]

Answer:

1280 in^3

Step-by-step explanation:

The volume of this rectangular prism-shaped body of water is

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V = (16 in)(10 in)(8 in) = 1280 in^3

The volume of the water is 1280 in^3

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Find all local extrema for f(x, y) = 2y3 + 12x2 − 24xy. (if an answer does not exist, enter dne.) local minimum (x, y) = local m
OlgaM077 [116]
f(x,y)=2y^3+12x^2-24xy
Find the first derivatives:
f'_x=24x-24y \\ f'_y=6y^2-24x.
Solve the system \left \{ {{f'_x=0} \atop {f'_y=0}} \right.:
\left \{ {{24x-24y=0} \atop {6y^2-24x=0}} \right. \rightarrow \left \{ {{x=y} \atop {6y^2-24y=0}}. The second equation has solutions y_1=0, \\ y_2=4 and then x_1=0, \\ x_2=4 and you have two points A_1(0,0), \\ A_2(4,4).

Find the first derivatives:
f^{''}_{xx}=24 \\ f^{''}_{xy}=f^{''}_{yx}=-24 \\ f^{''}_{yy}=12y and calculate \Delta=\left|  \left[\begin{array}{cc}24&-24\\-24&12y\end{array}\right]\right |=24\cdot 12y-(-24)^2=288y-576.
Since \Delta(A_1)=-576 and f^{''}_{xx}\ \textgreater \ 0, A_1 is a point of maximum and f(0,0)=0.
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Read 2 more answers
Determine if JK and LM are parallel ,perpendicular, or neither. J(13,-5) K(2,6) L(-1,-5) M(-4,-2)
barxatty [35]

Answer:

The lines are parallel

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

Remember that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

step 1

Find the slope JK

we have

J(13,-5),K(2,6)

substitute the values

m=\frac{6+5}{2-13}

m=\frac{11}{-11}

m_J_K=-1

step 2

Find the slope LM

we have

L(-1,-5),M(-4,-2)

substitute the values

m=\frac{-2+5}{-4+1}

m=\frac{3}{-3}

m_L_M=-1

step 3

Compare the slopes

m_J_K=-1

m_L_M=-1

so

m_J_K=m_L_M

therefore

The lines are parallel

7 0
3 years ago
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