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Gennadij [26K]
2 years ago
6

Ethan once heard that wearing colorful socks helped release your positive energy toward others. Being the scientist that he is,

he decided to put the claim to the test by running a well-designed study. He had 18 people wearing colorful socks at an auditorium where the rest of the people were wearing white socks. After carefully designing, collecting, and analyzing his data, he found no statistically significant difference between his sample of 18 participants and the rest of the population he studied regarding positive energy. What should Ethan conclude regarding the null hypothesis
Mathematics
1 answer:
Advocard [28]2 years ago
5 0

Answer:

The answer is "Choice A".

Step-by-step explanation:

Please find the complete question in the attachment file.

Throughout this question by acceptance of its zero hypotheses becomes equal to "the failure to accept the zero hypotheses." Its best answer is to refuse the null hypothesis or conclude how he had no effects on vibrant socks mostly on basis of this study, that's why the above given choice is correct.

You might be interested in
Y times 3=9 y =what
Nezavi [6.7K]

Answer: 3 Y=3

Step-by-step explanation:

Y×3=9

3×3=9

You can also check this by rearranging it and dividing 9 by 3.

9÷3=3.

This works for any similar problem.

Example:

Y×4=12 Y=? Y=3

Rearrange it and divide 12 by 4.

12÷4=Y

12÷4=3

So Y×4=12 because 3×4=12

Hope this helps!

6 0
3 years ago
Wastewater is filling barrels at the rate of 11 quarts per hour. The recycling facility picks up 120 full barrels on each trip,
dalvyx [7]
(1 h)/(11 qt) * (12 qt)/(1 barrel) * (120 barrels/pickup) * (1 day)/(24 h)
.. = 12*120/(11*24) day/pickup
.. = 5 5/11 days/pickup

120 barrels will be filled every 5 5/11 days. Some trips will be 5 days apart, some trips will be 6 days apart.
8 0
3 years ago
AJKL is similar to ARST. What is the value of x?
dlinn [17]

Answer:

15

Step-by-step explanation:

(12/8) ×10 is the correct answer

4 0
3 years ago
Read 2 more answers
A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective
andriy [413]

Answer:

(a) P(X \leq 20) = 0.9319

(b) Expected number of defective light bulbs = 15

(c) Standard deviation of defective light bulbs = 3.67

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....

where, n = number of samples taken = 150

            r = number of success

           p = probability of success which in our question is % of bulbs that

                  are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, \mu = n \times p = 150 \times 0.10 = 15

<u>Standard deviation of X</u>, \sigma = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.7

So, X ~ N(\mu = 15, \sigma^{2} = 3.7^{2})

Now, the z score probability distribution is given by;

                Z = \frac{X-\mu}{\sigma} ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X \leq 20) = P(X < 20.5)  ---- using continuity correction

    P(X < 20.5) = P( \frac{X-\mu}{\sigma} < \frac{20.5-15}{3.7} ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = n \times p = 150 \times 0.10 = 15.

Standard deviation of defective light bulbs is given by = S.D. = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.67

8 0
3 years ago
Help me please,Thanks
Ugo [173]

The answer to this question would be the last choice (this data has no outliers)

Explanation: The reason for this is that an outlier is basically any number or value that kind of stands off or is very separated from a set of data.

For example, if I had the numbers 1,2,3,2,9,5,7,5,8,4 and 47, 47 would definitely be an outlier as it's significantly greater than the rest of the data.

The data shown in your question doesn't vary a lot though, (it's contained within a range of 65 and 80- no number seems to be radically different).  

5 0
2 years ago
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