<u>Given</u>:
A rhino runs at a speed of about 28 miles per hour.
We need to determine the speed in feet per second.
<u>Converting miles to feet:</u>
The miles can be converted to feet by multiplying 5280 with 28 miles per hour.
Thus, we have;
Thus, the speed of the rhino in feet per hour is 147840
<u>Converting hours to seconds:</u>
The hours can be converted into seconds by dividing 147840 by 3600 (Because an hour has 60 seconds in a minute and 60 minutes in an hour)
Thus, we get;
Rounding off to the nearest whole number, we get;
Therefore, the speed of the rhino is 41 feet per second.
Hence, Option B is the correct answer.
Answer:
9x?lax+1)-1(2x+i)=0 p²-8p+4=0. (2x+1)(9x2-1)=0. 0-81764-40X4). (2x+1)(3x +1 (3x-1)=0 x= -1/2 x=-1/2 x=1/3. P= 843-4+213 x={-1/23 - 1 3 3 3 3 3. 4. Let 'n(x)=x2-Ox and g(x)=2x-7. Find all values of x, for which h(x) = g(x).
Step-by-step explanation:
Sheet #14-1. Quadratic Equations: Solving in Factored form. Algebra Common Core. MOVING WORDS. ... X+4 = 0 1 x +9=0 nr 3-01n-10-0 h=0 h-14=0. -4 -4 -9 -9. -3-3 tiu to. +14 114. X = -4 x=-9 n=-31 n =10 h = 14.
Part a
For horizontal 8*50% = 4 and for vertical 12*75%= 9.
So these values are less than the originals so the new frame is a reduction.
Part b
For horizontal 8*125% = 8*1.25 = 10 and for vertical 12*140% = 12*1.4 =16.8
So these values are greater than the originals sothe new frame is a enlargement.
The answer is D. Three over two
The height of the container be so as to minimize cost will be 1.20. inches.
<h3>How to calculate the height?</h3>
The volume of the box will be:
= 2x × 3x × h
= 6x²h
Volume = 6x²h
12 = 6x²h
h = 2x²
The cost function will be:
C = 2.60(2)(6x²) + 4.30(12x)h
C = 31.2x² + 51.6xh
Taking the derivative
62.4x + 51.6h
h = 1.20
Therefore, the height of the container be so as to minimize cost will be 1.20 inches.
Learn more about height on:
brainly.com/question/15557718
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