Solve 2y + 12 < 42 ???
1 answer:
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Answer:
As per the statement:
A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building.
⇒Length of the ladder against a building = 25 foot
and Length of the bottom of the ladder from the building= 7 feet.
You had Before the slip.
Let x be the height of the building where ladder hits the building
By Pythagoras theorem:
Here, Perpendicular side = Height of the building = x , Base = Length of the bottom of the ladder from the building = 7 foot and Hypotenuse side = 25 foot
Substitute the value to solve for x;
or
foot.
⇒Height of the building = 24 foot
Now, if the ladder slips down 4 feet.
You had after slip
⇒Now, the height of the building becomes = 24-4 = 20 foot.
Let y be the distance from the building wall
then by Pythagoras theorem;
foot.
We have to find how many feet will the bottom slide out.
Since, Originally the distance of the bottom from the building = 7 foot
And now, the distance is = 15 foot.
The bottom slide out will be = 15 - 7 =8 foot
Therefore, 8 feet will the bottom slide out
