The answer would be B because the 100 stays in there and you are adding 8% per year. Hope this helps.
The correct answer for the question shown above is: Gabriel should use 2 kilograms of compost.
The explanation is shown below:
1. To solve the exercise you must apply the following proccedure:
2. You have that He
wants it to be 2 parts compost to 10 parts potting soil and he
wants to end up with 10 grams of mix. Therefore:
=(2/12)x12 kilograms
=0.166x12 kilograms
=2 kilograms
For a smoothing constant of 0.2
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90
Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12
The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80
Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17
The mean forecast for period 11 is 53.56
Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
We can simplfiy to be 
.
We know that 
is 10 and 
is i, so the answer is 10i, or D.
Answer:
Step-by-step explanation:
352 is the answer
