Answer:
Land (Dr.) $1,800,000
Land Improvements $540,000
Building 2 $660,000
Building 1 demolish expense $346,400
Land grading expense $187,400
Building 3 construction cost $2,242,000
Land 2 improvement cost $168,000
Cash (Cr.) $22,143,800
Explanation:
Mitzu Co. has paid lump sum amount for 2 buildings and land. The building 1 has no value so its value is considered as zero and all the amount will be attributed to land and building 2. The company has also incurred costs for the demolish of building 1 which will be charged in the books of accounts as one off expense.
Answer:
A
Explanation:
A is the answer to the question
Answer:
Sure! Is there any platform you want to talk on?
Explanation:
Answer:
20.91%
Explanation:
Provided information
Average historical rate of return = 10.1 %
Variance = 0.0116751
By considering the above information, the standard deviation would be
= Square root of Variance
= 10.81%
So the upper percentage range of return would be
= Standard deviation + standard deviation
= 10.81% + 10.1%
= 20.91%
Since we have to find out the upper percentage so we added it otherwise we have to deduct it
Answer:
the breakeven cash inflow for the project is $131474
Explanation:
given data
cost of capital = 10 percent
initial investment = $1,000,000
useful life = 15 year
to find out
the breakeven cash inflow for the project
solution
first we consider here annual cash inflows that is = x
now break even point is the one at which the net present value of the project = 0
so we can say that here
Present value of cash inflows - Present value of cash outflows = 0 .................1
here we know Present value of cash inflows = x × PVAF ( 10%,15 years)
Present value of cash inflows = x × 7.6060
put value in equation 1 we get
x × 7.6060 - $1,000,000 = 0
solve and we get x
x = 
x = $131474
so the breakeven cash inflow for the project is $131474