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vaieri [72.5K]
4 years ago
10

Is this how you prime factorize? And is that the correct answer?

Mathematics
1 answer:
Anuta_ua [19.1K]4 years ago
8 0
You have the correct factor tree drawn out. Nice work on that. However, the final answer is not choice D.

The answer is actually choice C)

Notice how there are two '3's in the tree. One is below the 6 and the other is below the 126. So we really have 2*3*3*5*7 which turns into 2*3^2*5*7 which is what choice C is saying. 

Note: 2*3^2*5*7 is the same as 2*3^2*5*7 


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ANSWER ASAP!!
Alexeev081 [22]
<span>y = -2x + 3
y = -2x - 1

</span>-2x + 3 = -2x - 1

3=-1 false,
so the system has no solutions

Answer is A.0
6 0
4 years ago
The following quadrilateral is a parallelogram.
kvv77 [185]

Answer:

12

Step-by-step explanation:

By definition, opposite sides of a parallelogram are congruent.

8 0
4 years ago
What is the LCM of 4489​
vredina [299]

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67|4489

67|67

⠀ | 1

4 0
3 years ago
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Brilliant_brown [7]

Answer: 1 \frac{5}{27}

Step-by-step explanation:

\frac{8}{9}  x  1\frac{1}{3} = 1\frac{5}{27}

3 0
3 years ago
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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
3 years ago
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