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vaieri [72.5K]
4 years ago
10

Is this how you prime factorize? And is that the correct answer?

Mathematics
1 answer:
Anuta_ua [19.1K]4 years ago
8 0
You have the correct factor tree drawn out. Nice work on that. However, the final answer is not choice D.

The answer is actually choice C)

Notice how there are two '3's in the tree. One is below the 6 and the other is below the 126. So we really have 2*3*3*5*7 which turns into 2*3^2*5*7 which is what choice C is saying. 

Note: 2*3^2*5*7 is the same as 2*3^2*5*7 


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Choch Question 3 3.1 Construct the following triangles: 3.1.1 ADEF with EF = 7cm, ​
olasank [31]

We have to construct a triangle DEF with EF = 7 cm. It is given that we have to make an angle of 50⁰ at E and at F.

Steps to make a triangle DEF:

Step 1: Draw a line segment EF equal to 7 cm, using a ruler.

Step 2: Put the center of the protractor on the one end of the line segment that is at E and make the given angle that is 50⁰.

Step 3: Make the angle of 50⁰ at F by using protractor.

Step 4: Extend the line from E and F in the direction of 50⁰. After extending the line segments, we get an intersection point, name that point D..

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7 0
2 years ago
The map of a biking trail is drawn on a coordinate grid. The trail starts at P(−2, 2) and goes to Q(5, 2). It goes from Q to R(5
love history [14]

Answer:

The total length (in units) of the biking trail is 17 units.

Step-by-step explanation:

o find distance between points A(x¹, y¹) and B(x², y²), we use formula:

d = \sqrt{(x^{2}-x^{1})^{2}+(y^{2}-y^{1})^{2}}

The trail starts at P(−2, 2) and goes to Q(5, 2).

So, the distance PQ will be calculated as:

PQ = \sqrt{(5^{}-(-2)^{})^{2}+(2^{}-2^{})^{2}

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Then the trail goes from Q(5, 2) to R(5, −5).

So, the distance QR will be calculated as:

QR = \sqrt{(x^{2}-x^{1})^{2}+(y^{2}-y^{1})^{2}}

QR = \sqrt{(5^{}-5^{})^{2}+(-5^{}-2^{})^{2}

QR = 7 units

And then from R(5, −5) to S(8, −5).

RS = \sqrt{(8^{}-5^{})^{2}+(-5^{}-(-5)^{})^{2}}

QR = 3 units

Hence, the total length of the biking trail is:

                               PQ + QR + QR = 7 + 7 + 3 = 17 units

Keywords: distance formula, length

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Question in English:

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