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3 years ago

What is the awser to the equation (-x+2y=6)

1 answer:

6 0

You would add the x to both sides, cancelling out the x on the side with 2y. Then you divide by 2 leaving you with y=1/2x+3

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If the areas of the given pairs of shapes are equal, find the value of x.

den301095 [7]

Answer:

$x = 8cm$

Step-by-step explanation:

we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e

the area of the square equal to the area of the rectangle

therefore,

$\displaystyle \rm A _{square } = A _{rect}$

recall the formula of the area of square and rectangle so,

$\displaystyle {s}^{2} = lw$

now assign variables

$s \implies16cm$
$l \implies32cm$
$w \implies x$

thus substitute:

$\displaystyle 32cmx = {16cm}^{2}$

simplify square:

$\displaystyle 32cmx = 256cm^2$

divide both sides by 32:

$\displaystyle \boxed{x = 8cm}$

and we're done!

3 0

2 years ago

Read 2 more answers

Write the next three numbers in each counting sequence:<br> ...,40, 30, 20, ____, ____, ____,...

Leni [432]

10, 0, -10

You just have to subtract by 10

6 0

3 years ago

2+99393×17888÷2=? <br> WHATS THE ANSWER DAWG

Anna35 [415]

Answer:

888970994

Step-by-step explanation:

99393 * 17888 = 1777941984

1777941984/2 = 888970992

888970992+2 = 888970994

3 0

2 years ago

Read 2 more answers

Please Help 15 points! Emergency!

Semenov [28]

AA - f(t)=8000(1.5)^t

6 0

3 years ago

Read 2 more answers

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$