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Ainat [17]
3 years ago
8

HELP PLEASEE I’m stuck

Mathematics
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

:-):-)

Step-by-step explanation:

1) p<1000

2)p>500

3)By combining the above two, we get: 500<p<1000

Andre will agree as he thinks that the no. of paper clips in the box is less than 1000. But lin will not as she thinks that the no. of clips is more than 500.

4)This time, they both will agree as the no. of paper clips is more than 500 but less than 1000.

ElenaW [278]3 years ago
4 0
For number one, it’s asking for an inequality, which means that they want a “equation”. I put that in quotations because that is not the practical term. Andre says that he thinks there’s less than 1000

So that means, the answer is p < 1000

For number 2, it’s asking for the same thing. Lin says that it needs to be more than 500.

So that means, the answer is p > 500


For number 3, it’s just asking you if the number “487” is reasonable. You find that by plugging in the number 487 into “p”.

Is 487 < 1000 correct? Yes!
Is 487 > 500 correct? NO!

So that means for number three, you should put, “Lin and Andre would not agree. This is because the number 487 fits with Andre’s statement, but it does not fit with Lin’s. 487 is less than 1000, but it is not greater than 500.”

For number 4, you do the same thing. Plug in 742 into “p”.

Is 742 < 1000? Yes!
Is 742 > 1000? Yes!

So that means for number 4, you should put, “Lin and Andre would agree. This is because the number 742 fits with Andre’s and Lin’s statement. 742 is less than 1000, and it is greater than 500.”
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Step-by-step explanation:

Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.

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