Answer:
La constante de equilibrio (K) se expresa como la relación entre las concentraciones molares (mol/l) de reactivos y productos. Su valor en una reacción química depende de la temperatura, por lo que ésta siempre debe especificarse.
Explanation:
Static electricity is the result of an imbalance between negative and positive charges in an object. ... The rubbing of certain materials against one another can transfer negative charges, or electrons. For example, if you rub your shoe on the carpet, your body collects extra electrons.
This freezing point business is usually based on molality, that is moles solute per kilogram of solvent.
<span>molality = freezing point depression over Kf </span>
<span>In this case molality -10.3 degrees over -1.85 degrees Kf = 5.53 molal </span>
<span>This 5.53 molal solution is made up of l000 gms water and 5.53 moles glucose at 180 grams per mole for a total mass of 1997 grams </span>
<span>It volume would be l997 gms over 1.50 gms/ml or 1331 ml </span>
<span>We know that we have 5.53 moles of glucose dissolved in l331 ml of solution so now we can find how many moles of glucose in l000 ml or one liter of solution and this will be our Molarity </span>
<span>5.53 moles glucose over l331 ml = X moles glucose over l000 ml solution </span>
<span>cross multiply and solve for X moles glucose per liter solution </span>
<span>X = 4.15 moles glucose per liter = 4.15 Molar</span>
Answer:
- 58 kJ
Explanation:
The equation of the reaction is given as;
2NO2(g) → N2O4(g)
N2(g) + 202(g) → 2NO2(g) delta H = 67.7 kJ
Since NO2 is the reactant in the equation, we have to reverse this reaction. We now have;
2NO2(g) → N2(g) + 202(g) delta H = - 67.7 kJ
N2(g) + 202(g) → N2O4(g) delta H = 9.7 kJ
Since NO4 is the product in the equation, we don't have to do anything to this reaction.
Adding the two reactions;
2NO2(g) → N2(g) + 202(g) delta H = - 67.7 kJ
N2(g) + 202(g) → N2O4(g) delta H = 9.7 kJ
---------------------------------------------------------------- N2(g) and 2O2 (g) cancels out
2NO2(g) → N2O4(g) delta H = (-67.7 + 9.7) = - 58 kJ
Answer:
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Explanation: