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Nady [450]
3 years ago
15

How is an average mass different from a weighted mass

Chemistry
1 answer:
romanna [79]3 years ago
6 0

In an average mass, each entry has equal weight. In a weighted average, we multiply each entry by a number representing its relative importance.

Assume that your class consists of 15 girls and 5 boys. Each girl has a mass of 54 kg, and each boy has a mass of 62 kg.

<em>Average mass</em> = (girl + boy)/2 = (54 kg + 62 kg)/2 = <em>58 kg</em>

<em>Weighted average (Method 1) </em>

Use the <em>numbers of each</em> gender (15 girls + 5 boys) ,

Weighted average = (15×54 kg + 5×62 kg)/20 = (810 kg + 310 kg)/20

= 1120 kg/20 = <em>56 kg</em>.

If you put all the students on one giant balance, their total mass would be

1120 kg and the average mass of a student would be <em>56 kg. </em>

<em>Weighted average (Method 2) </em>

Use the <em>relative percentages</em> of each gender (75 % girls and 25 % boys).

Weighted average = 0.75×54 kg + 0.25×62 kg = 40.5 kg + 15.5 kg = <em>56 kg</em>

Each girl contributes 40.5 kg and each boy contributes 15.5 kg to the <em>weighted average</em> mass of a student.

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1.Balanced equation

C4H10 + 9 02 ==> 5H20 +4CO2

2. Volume of CO2 =596L

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1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;

CxHy +( x+y/4) O2 ==> y/2 02 + xCO2

Where x and y are number of carbon and hydrogen atoms respectively.

For butane (C4H10)

x=4 and y=10

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2. Mass of butane = 0.360kg

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Mole = mass/molar mass

Mole = 0.360/0.058= 6.2moles

From the stoichiometric equation

1mole of C4H10 will gives 4moles of CO2

Therefore

6.2moles of C4H10 will gives 4 moles of 24.8 moles of CO2

Using the ideal gas equation

PV=nRT

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