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3 years ago

A small pebble breaks off of a huge boulder. Th e pebble has the same density

Chemistry

2 answers:

AURORKA [14]3 years ago

8 0

Answer: Hmmmm. Let's see...

Explanation: A pebble has the same density and a boulder when it rolls down a hill. The pebble will most-likely roll down very fast which can make it dense.

<h2 /><h2>I really hope this helped! like at all...</h2><h2>Truthfully, I don't know a lot of this type of stuff.. But worth a shot, right?</h2>

Rashid [163]3 years ago

8 0

This statement can be true because the pebble and the huge boulder are made up from the same compound of materials meaning they will most likely have the same hardness when measured

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N2 (g) + 2O2(g) = 2NO2 (g) ΔH = 66.4 kJ 2NO (g) + O2 (g) = 2NO2 (g) ΔH = -114.2 kJ the enthalpy of the reaction of the nitrogen

RSB [31]

Answer:

ΔH = 180.6 kJ

Explanation:

Given that:

N2 (g) + 2O2(g) = 2NO2 (g) ΔH = 66.4 kJ

N2 (g) + O2 (g) = 2NO (g) ΔH = ????

The subtraction of both equations would yield the unknown ΔH , therefore:

ΔH = 66.4 - ( - 114.2 kJ)

ΔH = 180.6 kJ

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3 years ago

Read 2 more answers

Darryl finds a bottle of what looks like clear water, with dirt settled at the bottom. When he shakes the bottle, the water gets

Mazyrski [523]

Answer: The correct answer is Heterogeneous mixture

Explanation:

Heterogeneous mixture are those mixture in which:

Substance is distributed in non uniform manner.
Two distinct layers are formed

Thus when water and dirt are mixed together it results in the formation of a heterogeneous mixture and after sometimes two different layers will be observed.

Hence, in the bottle there is a heterogeneous mixture of water and dirt.

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3 years ago

A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work

DENIUS [597]

Data:
$V_{initial} = 590\:mL$
$T_{initial} = -55.0^0C$
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → $T_{initial} = 218.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 30.0^0C$
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → $T_{final} = 303.0\:K$

By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }$
Product of extremes equals product of means:
$218.0* V_{f} = 590*303.0$
$218.0 V_{f} = 178770$
$V_{f} = \frac{178770}{218.0}$
$\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark$

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