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3 years ago

Which of the following is considered an ignition source?

1 answer:

4 0

A.

Weldings sparks could start fire on wood.

Lightning can ignite a fire one a tall tree

Open flames can start another fire if made in contact especially with flammable substances

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What is the mass of 4.56 moles of copper (ii) fluoride

musickatia [10]

Answer:

463.0 g.

Explanation:

We can use the following relation:

<em>n = mass/molar mass.</em>

where, n is the mass of copper(ii) fluoride (m = 4.56 mol),

mass of copper(ii) fluoride = ??? g.

molar mass of copper(ii) fluoride = 101.543 g/mol.

∴ mass of copper(ii) fluoride = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

7 0

2 years ago

You are requested to reduce the size of 50 ton/hr of a given solid. The size of the feed is such 80% passes a 4-in (76.2 mm) scr

defon

Answer:

1) The power needed to process 50 ton/hr is 135.4 HP.

2) The void fraction of the bed is 0.37.

Explanation:

1) For this type of milling operations, we can estimate the power needed for an operation according to the work index (Ei), the passing size of the circuit feed (F80) and the passing size of the product (P80).

We assume the units of Ei are kWh/t.

The equation that relates this parameters and the power is (size of particles in μm):

$W=Ei*(\frac{10}{\sqrt{P80}} -\frac{10}{\sqrt{F80}} )\\\\W=9.45*(\frac{10}{\sqrt{3175\mu m}} -\frac{10}{\sqrt{76200mm}} )\\\\\\W=9.45*(0.1774+0.0362)=2.019 kWh/t$

The power needed to process 50 ton/hor is

$P=2.0194\frac{kWh}{Ton}*\frac{50Ton}{h}*\frac{1.341HP}{1kW}= 135.4 \, HP$

2) The density of the packed bed can be expressed as

$\rho=f_v*\rho_v+f_s*\rho_s$

being f the fraction and ρ the density of every fraction. We know that the density of the void is 0 (ρv=0) and that fv=1-fs (the sum of the fractions ois equal to the total space).

Then we can rearrange

$\rho=f_v*\rho_v+f_s*\rho_s\\\\\rho=f_v*0+(1-f_v)*\rho_s\\\\\rho/\rho_s=1-f_v\\\\f_v=1-\rho/\rho_s=1-990/1570=1-0.63=0.37$

The void fraction of the bed is 0.37.

6 0

3 years ago

Isotopes of the same element vary from each other in their number of:

Lina20 [59]

Answer: Neutrons vary from each other in their element

MARK ME BRAINLIST

5 0

2 years ago

The formula of heavy water

Crazy boy [7]

the formula of the heavy water is D2O

8 0

2 years ago

Help with the LAB answers

galben [10]

Answer : The reaction rate at $3^oC,24^oC,40^oC\text{ and }65^oC$ are $36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec$

Solution : Given,

Mass of tablet = 1000 mg

Volume of water = 0.200 L

Formula used :

$\text{Reaction rate}=\frac{\text{Mass of tablet}/\text{Volume of water}}{\text{Reaction time}}$

Now we have to calculate the reaction rate at different temperatures and reaction time.

$\text{Reaction rate at }3^oC=\frac{1000mg/0.200L}{138.5sec}=\frac{5000mg/L}{138.5sec}=36mg/L/sec$

$\text{Reaction rate at }24^oC=\frac{1000mg/0.200L}{34.2sec}=\frac{5000mg/L}{34.2sec}=142mg/L/sec$

$\text{Reaction rate at }40^oC=\frac{1000mg/0.200L}{26.3sec}=\frac{5000mg/L}{26.3sec}=190mg/L/sec$

$\text{Reaction rate at }65^oC=\frac{1000mg/0.200L}{14.2sec}=\frac{5000mg/L}{14.2sec}=352mg/L/sec$

Therefore, the reaction rate at $3^oC,24^oC,40^oC\text{ and }65^oC$ are $36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec$

5 0

3 years ago

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