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Natali [406]
3 years ago
15

How many grams of water can be produced when 65.5 grams of sodium hydroxide reacts with excess sulfuric acid? (4 points) You mus

t balance this equation first! H2SO4 + NaOH → H2O + Na2SO4 Show, or explain, all of your work along with the final answer.
Chemistry
1 answer:
stiks02 [169]3 years ago
5 0
Balanced Equation: H2SO4 + 2NaOH --> 2H2O + Na2SO4

Moles= Mass/RMM
= 65.5/40
= 1.6375

Mole Ratio = 2:2
= 1.6375

Mass (H2O) = 1.64 x 18
= 29.5 g
You might be interested in
If 38.5 grams of potassium react with excess oxygen gas, how many grams of potassium oxide can be produced? 4K + O2 yields 2K2O
Lera25 [3.4K]

Answer:

46.40 g.

Explanation:

  • It is a stichiometric problem.
  • The balanced equation of the reaction: 4K + O₂ → 2K₂O.
  • It is clear that 4.0 moles of K reacts with 1.0 mole of oxygen produces 2.0 moles of K₂O.
  • We should convert the mass of K (38.5 g) into moles using the relation:

<em>n = mass / molar mass,</em>

n = (38.5 g) / (39.098 g/mol) = 0.985 mole.

<em>Using cross multiplication:</em>

4.0 moles of K produces → 2.0 moles of K₂O, from the stichiometry.

0.985 mole of K produces → ??? moles of K₂O.

∴ The number of moles of K₂O produced = (0.985 mole) (2.0 mole) / (4.0 mole) = 0.4925 mole ≅ 0.5 mole.

  • Now, we can get the mass of K₂O:

∴ mass = n x molar mass = (0.5 mole) (94.2 g/mol) = 46.40 g.

6 0
3 years ago
What is the ionic compound formula for aluminum sulfide?
vfiekz [6]
Al2(SO4)3 would be the formula.
7 0
3 years ago
Read 2 more answers
What is the most appropriate unit of astronomical distance to represent the distance between an earth an orbiting space station
Reil [10]
Astronauts use "Astronomical Unit" to measure the distance between planets in our solar system "only". To measure long distances like between 2 galaxies, they use "light years". One Astronomical Unit = Average distance between sun and earth which is equal to 149.6 million kilometers. Ping me if you have any doubt.
4 0
3 years ago
What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

7 0
3 years ago
A patient needs to take 875mg twice daily The pills in the bottle are each 250mg How many pills does she wants to take 875mg
Angelina_Jolie [31]

Answer:

3.5 pill need to taken for completing dosage of 875 mg

Explanation:

Total dosage of medicine to be taken in a day

= 2 * 875 \\= 1750mg

Total weight of one pill = 250 mg

Number of pills required is equal to total dosage of medicine divided by the weight of one pill.

Hence,

Number of pills

= \frac{875}{250} \\= \frac{175}{50} \\= \frac{35}{10} \\= 3.5

6 0
3 years ago
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