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3 years ago

Why do California and Peru both have large deposits of gold?

1 answer:

3 0

Both California and Peru have or have had significant gold deposits because of their proximity to where two tectonic plate boundaries meet. Off the California coast there is the Pacific Plate and the North American Plate which meet at the San Andreas Fault but there also is the Farallon Plate which apparently has subducted somewhat below the North American Plate. Off Peru, the Nazca Plate is subducting under the South American Plate and which has caused the Andean orogeny.

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I need help!!! Please

irinina [24]

Answer:

Explanation:

7 0

3 years ago

How many formula units are contained in 23.5 g of Sb2S3

wolverine [178]

The molar mass of Sb2S3 is approximately equal to 339.7 g/mol. We calculate the number of moles of Sb2S3 by dividing the given mass by the molar mass.
n = 23.5 g / (339.7 g/mol)
n = 0.0692 mols
To calculate for the number of formula units, we multiply the number of mols by the Avogadro's number,
number of formula units = (0.0692 mols)(6.022 x 10^3)
= 4.167 x 10^22 formula units

7 0

2 years ago

Read 2 more answers

500 mL of a solution contains 1000 mg of CaCl2. Molecular weight of CaCl2 is 110 g/mol. Specific gravity of the solution is 0. C

dangina [55]

Answer:

a) 0,2% w/v

b) r=500

c) 0,0182 M

d) 0,0145 m

e) 0,0137 equivalents

Explanation:

a) % w/v means mass of solute in grams per 100 mililiter of solution. Thus:

%w/v= $\frac{1,000 g CaCl2}{500mL}$ ×100 = 0,2%w/v

b) Ratio strength is a way to express concentration. For w/v is in 1g of solute <em>r</em> mililiters of solution have. Thus, r = 500 because we have in the first 1 g of CaCl₂ in 500 mL of solution.

c) Molarity is moles of solute per liter of solution, thus:

1,000 g of CaCl₂ × $\frac{1mol}{110g}$ = 9,09×10⁻³ moles of CaCl₂

500 mL of solution × $\frac{1L}{1000mL}$ = 0,500 L of solution

M = $\frac{9,09x10^{-3} moles }{0,500 L}$ = 0,0182 M

d) Molality is moles of solute per kg of solution.

Specific gravity is the ratio between density of the solution and density of a reference substance (Usually water). With a specific gravity of 0,8:

kg of solution = 0,500 L of solution × $\frac{0,8 kg}{1L}$ =<em> </em><em>0,625 kg of solution</em>

m = $\frac{9,09x10^{-3}moles }{0,625 kg}$ = 0,0145 m

e) In a salt, equivalents are the number of moles ables to replace one mole of charge. In CaCl₂ is ¹/₂ because with ¹/₂ moles of CaCl₂ it is possible to replace 1 mole of charges. Thus, in 1,5 L there are:

1,5 L × $\frac{0,0182 CaCl2 moles}{1L}$ × $\frac{1equivalent}{2 moles}$ = 0,0137 equivalents

I hope it helps!

7 0

3 years ago

Consider the following voltaic cell:(j) In which direction do anions within the salt bridge move to maintain charge neutrality?

aniked [119]

In order to maintain neutrality, the negatively charged ions in the salt bridge will migrate into the anodic half-cell. A similar (but reversed) situation is found in the cathodic cell.

<h3>What purpose does a salt bridge serve in an oxidation process?</h3>

Anions (negatively charged particles) are added to the solution of the oxidation half of the cell by the salt bridge, and cations (positively charged particles) are added to the solution of the reduction half of the reaction.

<h3>What purpose does the salt bridge serve in a galvanic cell?</h3>

For instance, KCl, AgNO3, etc. In a galvanic cell, such as a voltaic cell or Daniel cell, salt bridges are typically used. A salt bridge's primary job is to assist in preserving the electrical neutrality of the internal circuit. Additionally, it aids in keeping the cell's response from reaching equilibrium.

Learn more about Salt bridge here:-

brainly.com/question/20345420

#SPJ4

7 0

1 year ago

A wave of infrared light has a speed of 6 m/s and a wavelength of 12 m. What is the frequency of this wave?

andreev551 [17]

Answer: The frequency of the wave is 0.5 hertz.

Explanation:

$\nu =\frac{c}{\lambda }$

$\nu$ = Frequency of the wave

$c$ = speed of the light in m/s

$\lambda$ = Wavelength of the wave.

Here in question we are given with speed of the infrared light. So, we will replace the value of speed of light(c) from the given value of the speed of the infrared light.

Speed of infrared light = 6 m/s

$\nu =\frac{\text{speed of infrared light}}{\lambda }=\frac{6 m/s}{12 m}=0.5 hertz$

The frequency of the wave is 0.5 hertz.

7 0

3 years ago

Read 2 more answers