How do you substitute 5x+4y=0 , x-y=9
1 answer:
You might be interested in
Answer:
Area of semicircle = 1/2(πr^2)
Area of quarter circle = 1/4(πr^2)
Step-by-step explanation:
The question is incomplete. You didn't provide the diagrams for the semicircle and quarter circle to evaluate the areas. I would explain how to find the area of a semicircle and quarter circle.
Area of a circle = πr^2
where r = radius and π = 3.14
If diameter (d) is given: d = 2r
To get radius, divide diameter by 2.
r = d/2
A semicircle is half of a circle.
Area of a semicircle is half the area of a circle.
Area of a semicircle = 1/2(πr^2)
A quarter circle is a quarter of a circle.
Area of a quarter circle is quarter of the area of a circle.
Area of a quarter circle = 1/4(πr^2)
Further explanation with diagram has been added as as an attachment.
