Question

Please help me

Answer 1

Answer:

This means that the coordinates of the vertex of the function are $(6,-31)$

Step-by-step explanation:

To find the x-coordinate of the vertex of a quadratic function, we can use the formula:

$x=\frac{-b}{2a}$

We are given the function $f(x)=x^2-12x+5$

In this function, $a=1$ and $b=-12$

Now we can input these values into our formula

$x=\frac{-(-12)}{2(1)} \\\\x=\frac{12}{2} \\\\x=6$

This means that the x-value of the vertex is located at $x=6$. To find the other half of the coordinate pair, we can now plug $x=6$ into the given function

$f(6)=(6)^2-12(6)+5\\\\f(6)=36-72+5\\\\f(6)=41-72\\\\f(6)=-31$

This means that the coordinates of the vertex of the function are $(6,-31)$