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Morgarella [4.7K]
3 years ago
9

Consider a perfectly reflecting mirror oriented so that solar radiation of intensity I is incident upon, and perpendicular to, t

he reflective surface of the mirror.
(a) If the mirror has surface area A, what is Frad, the magnitude of the average force due to the radiation pressure of the sunlight on the mirror?
Express your answer in terms of the intensity I, the mirror's surface area A, and the speed of light c.
Physics
1 answer:
VLD [36.1K]3 years ago
4 0

Answer:

Frad = 2IA/C

Explanation:

see attached file

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A rope is attached to a block. The rope pulls on the block with a force of 240 N, at an angle of 40 degrees to the horizontal (t
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Answer:

X Component is 183.85N

Explanation:

The x component of the force on the block due to the rope;

X = F cos @ where if is the force, @ is the angle mad with the block.

X = F cos @

X = 240 cos 40

Cos 40= 0.7660, so

X = 240 × 0.7660

X component= 183.85N// rounded to two decimal places.

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A train moves at constant velocity of 90km/h. How far will it go in 0.25h.
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In a quarter of an hour it will travel 1/4 x 90 = 22.5Km
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Which two statements describe what happens in both nuclear fusion and nuclear fission reactions?
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In the ballistic pendulum experiment (A.K.A conservation of momentum & energy), the velocity of the projectile was measured
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Answer: The combined velocity = 0.413m/a

Maximum angle Ø = 54.7

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3 years ago
A box of mass 3.6 kg is lifted 5.4 m above the
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So, the energy change that occurs is 190.512 J.

<h3>Introduction</h3>

Hello ! I am Deva from Brainly Indonesia will help you regarding energy and its transformation. In this case, it's the use of energy from the lifter to be equivalent to the change in the object's potential energy. Why potential energy? Because the box undergoes a change in height and the potential energy specializes at a certain height. Work (W) due to change in potential energy (\sf{\Delta PE}) can be realized in the equation :

\sf{W = \Delta PE}

\sf{W = m \cdot g \cdot h_2 - m \cdot g \cdot h_2}

\boxed{\sf{\bold{W = m \cdot g \cdot (h_2 - h_1)}}}

With the following condition :

  • W = work of subject (J)
  • \sf{\Delta PE} = change of potential energy (J)
  • m = mass (kg)
  • g = acceleration of the gravity (m/s²)
  • \sf{h_2} = final height (m)
  • \sf{h_1} = initial height (m)

<h3>Problem Solving</h3>

We know that :

  • m = mass = 3.6 kg
  • g = acceleration of the gravity = 9.8 m/s²
  • \sf{h_2} = final height = 5.4 m
  • \sf{h_1} = initial height = 0 m

What was asked :

  • W = work of subject = ... J

Step by step :

\sf{W = \Delta PE}

\sf{W = m \cdot g \cdot (h_2 - h_1)}

\sf{W = 3.6 \cdot 9.8 \cdot (5.4 - 0)}

\sf{W = 3.6 \cdot 9.8 \cdot 5,4}

\boxed{\sf{W = 190.512 \: J}}

So, the energy change that occurs is 190.512 J.

7 0
3 years ago
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