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3 years ago

How can a rocket be propelled forward in space where there is no air to push against?

Physics

1 answer:

pychu [463]3 years ago

3 0

Answer:

Explanation:

In space, rockets zoom around with no air to push against. ... When a rocket shoots fuel out one end, this propels the rocket forward — no air is required. NASA says this principle is easy to observe on Earth. If you stand on a skateboard and throw a bowling ball forward, that force will push you and the skateboard back.

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What is the kinetic theory of matter? How does it relate to the motion of molecules?

Charra [1.4K]

Answer:

Explanation:

Kinetic energy is energy that an object has because of its motion. The Kinetic Molecular Theory explains the forces between molecules and the energy that they possess. This theory is based on three theories about matter. Matter is composed of small particles (atoms, molecules, and ions).

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2 years ago

Juans mother drives 7.25 miles southwest to her favorite shopping mall. What is the average velocity of her automobile if she ar

Irina-Kira [14]

21.75 Miles Per Hour

I got this by multiplying 7.25(3) because I know 20 minutes is 1/3 of 1 he

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3 years ago

Help please it's a test

UNO [17]

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3 years ago

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Vlad [161]

Answer:

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Explanation:

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2 years ago

A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline

balandron [24]

Answer:

2.78m/s²

Explanation:

Complete question:

A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?

According to Newton's second law of motion:

$\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\$

Where:

$\mu$ is the coefficient of friction

g is the acceleration due to gravity

Fm is the moving force acting on the body

Ff is the frictional force

m is the mass of the box

a is the acceleration'

Given

$\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2$

Required

acceleration of the box

Substitute the given parameters into the resulting expression above:

Recall that:

$gsin\theta - \mu g cos\theta = a_x\\$

9.8sin30 - 0.25(9.8)cos30 = ax

9.8(0.5) - 0.25(9.8)(0.866) = ax

4.9 - 2.1217 = ax

ax = 2.78m/s²

Hence the acceleration of the box as it slides down the incline is 2.78m/s²

5 0

3 years ago