How can a rocket be propelled forward in space where there is no air to push against?
1 answer:
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We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is
where
Now we find the moment of inertia by integrating from
to 
The moment of inertia is
(from (-a/2) to
(a/2))
where
Now we find the moment of inertia by integrating from
The moment of inertia is
Answer:
A) E = 4.96 x 10³ eV
B) E = 4.19 x 10⁴ eV
C) E = 3.73 x 10⁹ eV
Explanation:
A)
For photon energy is given as:
where,
E = energy of photon = ?
h = 6.625 x 10⁻³⁴ J.s
λ = wavelength = 0.25 nm = 0.25 x 10⁻⁹ m
Therefore,
<u>E = 4.96 x 10³ eV</u>
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B)
The energy of a particle at rest is given as:
where,
E = Energy of electron = ?
m₀ = rest mass of electron = 9.1 x 10⁻³¹ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
<u>E = 4.19 x 10⁴ eV</u>
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C)
The energy of a particle at rest is given as:
where,
E = Energy of alpha particle = ?
m₀ = rest mass of alpha particle = 6.64 x 10⁻²⁷ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
<u>E = 3.73 x 10⁹ eV</u>