A rope is attached to a block. The rope pulls on the block with a force of 240 N, at an angle of 40 degrees to the horizontal (t
his force is equal to the tension in the rope). What is the x-component of the force on the block due to the rope?
2 answers:
Answer:
The x-component of the force on the block due to the rope is 183.8 newtons
Explanation:
See the picture attached.
Because the force F on the block due the rope is applied at an angle of 40 degrees respect the horizontal, it has a component on x (Fx) and a component on y (Fy) we should find the x component. We should use trigonometric relations for right tringle. We need the equation that relates hypotenuse (F) and adjacent side (Fx), this relation is:
solving for Fx:
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In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.
<u>Explanation:</u>
An object experiences impulse due to the force exerted upon it in a particular time period.
i.e.
Where,
F - Force acted upon the object
- time interval for which the force act
According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).
Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.