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3 years ago

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A rope is attached to a block. The rope pulls on the block with a force of 240 N, at an angle of 40 degrees to the horizontal (t

his force is equal to the tension in the rope). What is the x-component of the force on the block due to the rope?

2 answers:

Tom [10]3 years ago

3 0

Answer:

X Component is 183.85N

Explanation:

The x component of the force on the block due to the rope;

X = F cos @ where if is the force, @ is the angle mad with the block.

X = F cos @

X = 240 cos 40

Cos 40= 0.7660, so

X = 240 × 0.7660

X component= 183.85N// rounded to two decimal places.

LenKa [72]3 years ago

3 0

Answer:

The x-component of the force on the block due to the rope is 183.8 newtons

Explanation:

See the picture attached.

Because the force F on the block due the rope is applied at an angle of 40 degrees respect the horizontal, it has a component on x (Fx) and a component on y (Fy) we should find the x component. We should use trigonometric relations for right tringle. We need the equation that relates hypotenuse (F) and adjacent side (Fx), this relation is:

$cos 40 =\frac{F_x}{F}$

solving for Fx:

$F_x = F*cos 40 = 240*cos(40)$

$F_x = 183.8 N$

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