This question is not complete.
The complete question is as follows:
One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?
Explanation:
a. Using the expression;
T = 2π√R/g
where R = radius of the space = diameter/2
R = 800/2 = 400m
g= acceleration due to gravity = 9.8m/s^2
1/T = number of revolutions per second
T = 2π√R/g
T = 2 x 3.14 x √400/9.8
T = 6.28 x 6.39 = 40.13
1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute
The planetary wind belts in the troposphere are primarily caused by the Earth's rotation and the unequal heating of Earth's surface.
Planetary wind belts are vast movements and they are driven by the circulation of air. The Sun's heat causes the winds around the world. It heats the tropical zone primarily than the polar regions because the sun's rays are more direct at the equator.
Answer:
See explanations below
Explanation:
1) KE = 1/2mv²
mass m = 0.142kg
v = 40m/s
KE = 1/2 * 0.142 * 40^2
KE = 1/2 * 0.142 * 1600
KE = 800*0.142
KE = 113.6Joules
2) KE = 1/mv^2
KE = 196
mass m = ?
velocity v = 52m/s
Substitute
196 = 1/2*m*52²
196 = 1352m
m = 196/1352
m = 0.145kg
Hence the mass of the baseball is 0.145kg
3) KE = 1/2mV^2
288 = 1/2 * 4v²
288 = 2v²\
v² = 288/2
v² = 144
v = 12m/s
The velocity of the shotput is 12m/s
Answer:
2.75 m/s^2
Explanation:
The airplane's acceleration on the runway was 2.75 m/s^2
We can find the acceleration by using the equation: a = (v-u)/t
where a is acceleration, v is final velocity, u is initial velocity, and t is time.
In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1
a = 2.75 m/s^2