We will apply the concepts related to energy conservation to develop this problem. In this way we will consider the distances and the given speed to calculate the final speed on the path from the sun. Assuming that the values exposed when saying 'multiply' is scientific notation we have the following,
The difference of the initial and final energy will be equivalent to the work done in the system, therefore
Here,
m = Mass
= Final velocity
G = Gravitational Universal Constant
M = Mass of the Sun
m = Mass of the comet
= Initial Velocity
Rearranging to find the final velocity,
Replacing with our values we have finally,
Therefore the speed is 75653m/s
Answer:
2.58 x 10⁸ m/s
Explanation:
Time dilation fomula will be applicable here, which is given below.
t = \frac{T}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}
Where T is dilated time or time observed by clock in motion , t is stationary time , v is velocity of clock in motion and c is velocity of light .
c is 3 times 10⁸ ms⁻¹ , T is 7.24 h , t is 3.69 h. Put these values in the formula
7.24 = \frac{3.69}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}\\
\frac{v^2}{c^2}=0.744\\\\
v=2.58\times 10^8
Answer:
Explanation:
At the bottom the tension would be upwards and the weight downwards, their difference being the centripetal force. Taking the upwards direction as positive we then have:
where we have used the equation for centripetal acceleration. Thus we have:
