Answer:
$0.025x² . . . where x is a number of percentage points
Step-by-step explanation:
The multiplier for semi-annual compounding will be ...
(1 + x/2)² = 1 + x + x²/4
The multiplier for annual compounding will be ...
1 + x
The multiplier for semiannual compounding is greater by ...
(1 + x + x²/4) - (1 + x) = x²/4
Maria's interest will be greater by $1000×(x²/4) = $250x², where x is a decimal fraction.
If x is a percent value, as in x = 6 when x percent = 6%, then the difference amount is ...
$250·(x/100)² = $0.025x² . . . where x is a number of percentage points
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<u>Example</u>:
For x percent = 6%, the difference in interest earned on $1000 for one year is $0.025×6² = $0.90.
Your answer would be A because $4800 is your starting number and it increases 2% every year. How much is it in 20 years?
You use the formula ab^x
a is your starting number
b is the percentage
x is always the length of time
Since you are increasing and trying to get its worth larger than what it was before you use a number larger than one hundred percent in this case the number would be 1.02.
Y=4800(1.02)^20
Y=$7132.55
Answer:
7
Step-by-step explanation:
You divided both 28 and 4 and you will get 7 as your answer.
5.333 OR 5 1/3
just plug it in the calculator
you will get your answer
