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Ann [662]
3 years ago
3

Which equation represents a line that passes through (–2, 4) and has a slope of ?

Mathematics
2 answers:
sp2606 [1]3 years ago
8 0

y – 4 = (x + 2)

<h3>Further explanation</h3>

We will determine the line equation. Later the equation will be arranged in slope-intercept, point-slope, and standard form.

<u>Given:</u>

  • A line that passes through (–2, 4).
  • A slope of 1.  

<u>The Process:</u>

  • Slope or gradient m = 2.
  • Point (x₁, y₁) is (-2, 4).  

<u>Part-1</u>

\boxed{ \ Slope-intercept \ form: y = mx + c \ }

Substitution.

\boxed{ \ \ m = 1 \rightarrow y = x + c \ }

The line passing through the point (-2, 4).

\boxed{ \ x_1 = -2, y_1 = 4 \ } \rightarrow \boxed{ \ 4 = (-2) + c \ } \rightarrow \boxed{ \ c = 6 \ }

Thus the slope-intercept form is \boxed{\boxed{ \ y = x + 6 \ }}

<u>Part-2</u>

\boxed{ \ Point-slope \ form: y - y_1 = m(x - x_1) \ }

\boxed{ \ m = 1 \rightarrow y - y_1 = (x - x_1) \ }

The line passing through the point (-2, 4).

\boxed{ \ x_1 = -2, y_1 = 4 \ } \rightarrow \boxed{ \ y - 4 = (x - (-2)) \ }

Thus the point-slope form is \boxed{\boxed{ \ y - 4 = (x + 2) \ }}

<u>Part-3</u>

\boxed{ \ Standard \ form: ax + by = k \ }

From the results of Part-1, we set the position of the variables.

\boxed{ \ y = x + 6 \ }

\boxed{ \ x + 6 = y \ }

\boxed{ \ x - y = - 6 \ }

Thus the standard form is \boxed{\boxed{ \ x - y = - 6 \ }} \ or \ \boxed{\boxed{ \ y - x = 6 \ }} \ or \ \boxed{\boxed{ \ x - y + 6 = 0 \ }}

<h3>Learn more</h3>
  1. Find out ordered pairs could be points on a line that is perpendicular to another line  brainly.com/question/2601054  
  2. Determine the line equation, in slope-intercept form, that is parallel to the given line and passes through a point  brainly.com/question/1473992  
  3. Determine an equation represents Nolan’s line brainly.com/question/2657284

Keywords: the line equation, slope-intercept form, standard form, point-slope, gradien, a line that passes through (–2, 4)

worty [1.4K]3 years ago
5 0
Slope = 1

equation
y - y1 = m(x - x =1)
<span>a line that passes through (–2, 4)
so equation should be

y - 4 = 1(x +2)
or
y - 4 = (x + 2)

answer is first one.

</span><span>y – 4 = (x + 2)</span>
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