Answer: a) , where 'A' is the value of car after 't' years.
b) $12446.784
Step-by-step explanation:
Given: A new car that sells for $21,000 depreciates (decreases in value) 16% each year.
Then a function that models the value of the car will be
, where 'P' is the selling price of car, 'r' is the rate of depreciation in decimal, 't' is the time in years and 'A' is the value of car after 't' years.
Thus after substituting given value, the function becomes
To find the value after 3 years, substitute t=3 in the above function.
Hence the value of car after 3 years=$12446.784
Answer:
We set up 2 equations
A) C + A = 100
B) 5C + 12A = 780
We multiply A by -5
A) -5C -5A = -500 then we add B
B) 5C + 12A = 780
7A = 280
Number of Adults = 40
5C = 780 - 40*12
5C = 780 -480
5C = 300
Number of Children = 60
Step-by-step explanation:
56.7 should be the right answer
I think its 8m/h or somethan but idrk. Like it doesnt specify how long it took him the run the 2 hours so idrk. Or it would be 2m/d + 6m/h with d=day
Answer:
15
Step-by-step explanation:
0.3% of 5000
= (0.3/100) x 5000
= 0.3 x 50
= 15
