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alexira [117]
3 years ago
15

GIVING BRAINLIEST!!!!!!!! 1/2 x(6X4)+3+2 SHOW UR WORK PLS

Mathematics
1 answer:
mezya [45]3 years ago
7 0

Answer: 1/2 times 6x equals 3x  and then you do 1/2 times 4 and that equals 2 then multiply the 3 and 4 in the parenthesis and that is 12 then add 12 to the 3 and 2 and your answer is 17.

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=I%20don%27t%20get%20this" id="TexFormula1" title="I don't get this" alt="I don't get this" ali
Sedaia [141]

Answer:

does anybody?

Step-by-step explanation:

attach work

5 0
3 years ago
Read 2 more answers
Need help on this one
Furkat [3]
The trick here is to not use sin and cos at all.

The -13/15 is the x coordinate of a line from the origin to the unit circle (the line with angle theta). That happens to be the cos(theta).

The y coordinate is the sin(theta).

You can draw this as a triangle where x^2 + y^2 = 1.

So y = √(1 - (13/15)^2) ≈ 0.49889. But your exact answer should be:

sin(\theta) = \sqrt{1-(\frac{13}{15})^2} = \frac{2\sqrt{14}}{15}


5 0
4 years ago
1. The manager of FrozonAir Refrigerator factory notices that on Monday it cost the company a total of $25,000 to build 30 refri
Vinvika [58]

Answer:

The fixed costs per day for the factory is $10,000 and marginal cost of one refrigerator for $500

Step-by-step explanation:

Let

Cost per refrigerator (marginal cost) = r

Fixed costs per day for the factory = f

Total cost = variable cost + fixed cost

Monday

25,000 = 30r + f

Tuesday

30,000 = 40r + f

Using Monday,

f = 25000 -30r

Substitute f = 25000 - 30r into Tuesday

30,000 = 40r + f

30,000 = 40r + (25,000 -30r)

30,000 = 40r + 25,000 - 30r

Collect like terms

30,000 - 25,000 = 40r - 30r

5,000 = 10r

Divide both sides by 10

r = 5,000 / 10

= 500

r = $500

Substitute r= 500 into Monday equation

f = 25,000 -30r

= 25,000 - 30(500)

= 25,000 - 15,000

= 10,000

f = $10,000

Therefore, the fixed costs per day for the factory is $10,000 and marginal cost of one refrigerator for $500

7 0
3 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
There were 125 females and 100 males present at the high school pep rally. Find the ratio of males to the total number of people
riadik2000 [5.3K]
Total number of people = 125 + 100 = 225

Number of males = 100

Set as ratio

100:225

Simplify to 4:9 (can not simplify further without having decimals but you can’t have half a person)
5 0
3 years ago
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