For number 16 we need to write the data as a ratio then convert to a unit rate (amount per 1)...
308/14 = x/1
Cross multiply
14x = 308
x = 308/14
x = 22
So the fuel efficiency is
22 miles per 1 gallon or
22/1
For number 17, since the car was driven at 48 mph, we just have to divide distance driven by speed to get how long it took...
288 miles ÷ 48 mph =
6 hours
7.5. 10.5*5 and divide that by 7
Answer:
10. 7n - 1 < -8
Isolate the variable, n. Do the opposite of PEMDAS. Treat the < as equal sign, what you do to one side, you do to the other. First, add 1 to both sides:
7n - 1 (+1) < - 8 (+1)
7n < - 8 + 1
7n < - 7
Isolate the variable, n. Divide 7 from both sides:
(7n)/7 < (-7)/7
n < -7/7
n < -1
n < -1 is your answer.
11. 3 > -7v + 4v
Combine like terms, then isolate the variable, v. First, add -7v and 4v together.
3 > (-7v + 4v)
3 > (4v - 7v)
3 > (-3v)
Isolate the variable, v. Divide -3 from both sides. Note that since you are dividing a negative number, you must flip the sign:
(3)/-3 > (-3v)/-3
3/-3 > v
-1 < v
v > -1 is your answer.
~
Answer:
The first amount is larger by 25% or .25a
Step-by-step explanation:
Lets increase a by 50%
The increase is .5a
So the new value is a + .5a = 1.5a
Now we will decrease the new value by 50%
decrease = .5 (1.5a) = .75a
The new value of a is 1.5a - .75a = .75a
a > .75a
a - .75a = .25a
a is bigger than .75a by .25a
