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miss Akunina [59]
3 years ago
13

A soccer player runs up behind a 0.450-kg soccer ball traveling at 3.20 m/s and kicks it in the same direction as it is moving,

increasing its speed to 12.8 m/s. What magnitude impulse did the soccer player deliver to the ball?
Physics
1 answer:
NISA [10]3 years ago
7 0

To develop this problem it is necessary to use the concepts related to Impulse.

The impulse is defined as the change in velocity at the rate of mass, that is

L = m\Delta V,

Where,

m = Mass

\Delta V = Change in Velocity

This change in velocity can be expressed as,

L = m(v_2-v_1)

L = 0.45*(12.8 - 3.2)

L = 0.45*9.6

L= 4.32 Kg.m/s

Therefore the magnitude of the impulse is 4.32 Kg.m/s

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3 years ago
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A thundercloud has an electric charge of 48.8 C near the top of the cloud and –41.7 C near the bottom of the cloud. The magnitud
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Answer: 1.51 km

Explanation:

<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.

Or,   \vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}

Where Q1 and Q2 are magnitude of two charges and r is distance between them:

<u>Given:</u>

Q1 = Charge near top of cloud = 48.8 C

Q2 = Charge near the bottom of cloud = -41.7 C

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k = 8.99 x 109Nm^2/C^2

<u>So,</u>

\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514  \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}

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3 0
2 years ago
It's velocity changes, but its speed remains the same.<br> The<br> true or false
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True

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But if it now starts moving along y axis, it's velocity is 1j (j represents unit vector along y axis). Hence velocity changes with direction.

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3 years ago
A truck traveling down the highway collides with a slower moving mosquito traveling in the same direction. Which of the followin
Ipatiy [6.2K]

Answer:

B. The truck and mosquito exert the same size force on each other.

Explanation:

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In this case, we can call

object A = the truck

object B = the mosquito

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