All categories

3 years ago

Which one of the following is a balanced equation?

Physics

1 answer:

yarga [219]3 years ago

5 0

D. 2Na (s) + MgF2 → 2NaF (s) + Mg (s)

Explanation:

From the given choices, 2Na (s) + MgF2 → 2NaF (s) + Mg (s) is balanced

A balanced equation is one that obeys the law of conservation of matter which states that "matter is neither created nor destroyed but transformed from one form to another".

We expect to find the same name of atoms on both sides of the equation.

let us examine the choices;

Zn (s) + HCl (g) → ZnCl2 (s) + H2 (g)

Reactants Products

Zn 1 1

H 1 2

Cl 1 2

Na (s) + O2 (g) → Na2O

Reactants products

Na 1 2

O 2 1

Na (s) + MgF2 → 2NaF (s) + Mg (s)

Reactants products

Na 1 2

Mg 1 1

F 2 2

2Na (s) + MgF2 → 2NaF (s) + Mg (s)

Reactants products

Na 2 2

Mg 1 1

F 2 2

learn more:

Balanced equation brainly.com/question/2947744

#learnwithBrainly

You might be interested in

If the bar magnet is flipped over and the south pole is brought near the hanging ball, the ball will be?

disa [49]

The ball may attracted to the magnet.

<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>

From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
Steel is a magnetic material.
Magnetic materials gets attracted to the magnet at both the North and South pole.
This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.

So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.

Learn more about the bar magnet:

brainly.com/question/27943723

#SPJ4

7 0

1 year ago

Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of

Elanso [62]

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

$s = at^2/2 = 5t^2/2 = 2.5t^2$

We can take derivative of this with respect to time t to get the equation of slope:

$s' = (2.5t^2)' = 2*2.5t = 5t$

As time t increase, the slope would increases with time as well.

6 0

3 years ago

The electric flux through a square-shaped area of side 5 cm near a very large, thin, uniformly-charged sheet is found to be 3\ti

deff fn [24]

Answer:

Explanation:

Given

side of square shape $a=5\ cm$

Electric flux $\phi =3\times 10^{-5}\ N.m^2/C$

Permittivity of free space $\epsilon_0=8.85\times 10^{-12} \frac{C^2}{N.m^2}$

Flux is given by

$\phi =EA\cos \theta$

where E=electric field strength

A=area

$\theta$ =Angle between Electric field and area vector

$E=\frac{\phi }{A\cos (0)}$

$E=\frac{3\times 10^{-5}}{25\times 10^{-4}\times \cos(0)}$

$E=0.012\ N/C$

and Electric field by a uniformly charged sheet is given by

$E=\frac{\sigma }{2\epsilon_0}$

where $\sigma$ =charge density

$=\frac{\sigma }{\epsilon_0}$

$\sigma =0.012\times 8.85\times 10^{-12}$

$\sigma =2.12\times 10^{-13}\ C/m^2$

5 0

3 years ago

A larger truck takes more force to move<br><br> What law of motion is it?

Y_Kistochka [10]

Newton's Second Law would probably best describe this.
F = ma
Where F = force
m = mass
a = acceleration

The force required is dependant on the mass, and where the mass is greater, the force required will be greater.

6 0

3 years ago

A pitcher throws a baseball with a mass of 143 g horizontally at a speed of 38.8 m/s (87 mi/h). The hitter's bat is in contact w

SIZIF [17.4K]

Answer:

F = −10093.41 N

Explanation:

Given that,

Mass of a baseball, m = 143 g = 0.143 kg

Initial speed of the baseball, u = +38.8 m/s

The hitter's bat is in contact with the ball for 1.20 ms and then travels straight back to the pitcher's mound at a speed of 45.9 m/s, v = -45.9 m/s

We need to find the average force exerted on the ball by the bat. So, Force is given by :

$F=ma$

a is acceleration

$F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.143\times (-45.9-(38.8))}{1.2\times 10^{-3}}\\\\F=-10093.41\ N$

So, the average force exerted on the ball by the bat has a magnitude of 10093.41 N.

8 0

3 years ago