To which class of compounds does ammonia belong?
1 answer:
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Answer:
a = 0.1067 [m/s²]
Explanation:
In order to solve this problem, we must first draw a free body diagram with the forces acting on it.
a)
In the attached image we can find the free body diagram.
b)
The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.
∑Fx = Fr
where:
Fr = resultant force [N] (units of Newtons)
c)
Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.
∑F = m*a
where:
m = mass = 2250 [kg]
a = acceleration [m/s²]
Answer:-1 m/s/s
Explanation:
Answer:
<h2>v= 2.74m/s</h2>Explanation:
We can solve for the initial velocity using the first equation of motion
where
v= final velocity
u= initial velocity
a= acceleration
t= time in seconds
Given data
final velocity= 2.41 m/s
initial velocity v =?
time t= 2.5 seconds
acceleration a=
substituting we have
v= 2.41+0.13(2.5)
v= 2.41+0.325
v= 2.735m/s
v= 2.74m/s
the final velocity is 2.74 m/s