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Illusion [34]
2 years ago
11

PLZ HELPWILL GIVE BRAINLIEST 49 POINTS!!!

Physics
2 answers:
lana66690 [7]2 years ago
4 0

Hey there!

We understand that those statements that are listed below are the statements that would analyze the diagram.

A.  The angle of incidence is degrees.

B.  The angle of reflection is degrees.    

C. The angle of refraction is degrees.

Let's start out with the first one as listed.

A.  The angle of incidence is degrees.

let's consider the incidence ray. We wonder, how many degrees would be this ray. At noted in the diagram above, it would be considered to be 40°.

How?

Both 50° and 50° are considered to be normal, right in the middle.

We do 40°+40°=80°+ (both 50° with are normal) 50°+50° = 180°.

Therefore, we get the gist of how this incidence would be 50°.

∡=50 degrees.

___________________________________________________________

B.  The angle of reflection is degrees.

We see that both sides are equally measured. Both 50°+40°= 90°, as well for the other side. 50°+40°= 90. The reflection of this would be 90°.

∡90° degrees.

___________________________________________________________

C. The angle of refraction is degrees.

Refraction come from what refracts from the other side. In this case, we see that 20° would be your answer, because from this, as the diagram shows, we can see how 20° refracts straight from the 70° on the left.

∡20° degrees.

____________________________________________________________

Feel free to ask more questions at Brainly!

gulaghasi [49]2 years ago
3 0

Angle A - 50 degrees

Angle B - 90 degrees

Angle C - 20 degrees

Hope This Helps!

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The height above the ground from where the skier start is 11.5 m.

<h3>Conservation of energy</h3>

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gh = ¹/₂v²

h = \frac{v^2}{2g} \\\\h = \frac{15^2}{2 \times 9.8} \\\\h = 11.5 \ m

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8 0
2 years ago
Using a crowbar, a person can remove a nail by exerting little force, whereas pulling directly on the nail requires a large forc
algol [13]
Here we deal with a lever law. It states that product of force and distance from a fixed point on a lever is equal on both sides.

F₁*d₁ = F₂*d₂

By analysing this formula we can see that applying small force on a great length equals great force on a small length.
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A steel beam of mass 1975 kg and length 3 m is attached to the wall with a pin that can rotate freely on its right side. A cable
Nuetrik [128]

Answer:

a) 29062.125 N·m

b) 0 N·m

c) Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) T = 11186.02 N

Explanation:

We are given

Beam mass = 1975 kg

Beam length = 3 m

Cable angle = 60° above horizontal

a) We have the formula for torque given as follows;

Torque about the pin = Force × Perpendicular distance of force from pin

Where the force = Force due to gravity or weight, we have

Weight = Mass × Acceleration due to gravity = 1975 × 9.81 = 19374.75 N

Point of action of force = Midpoint for a uniform beam = length/2

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Torque due to gravity = 19374.75 N × 1.5 m = 29062.125 N·m

b) Torque about the pinned end due to the contact forces between the pin and the beam is given by the following relation;

Since the distance from pin to the contact forces between the pin and the beam is 0, the torque which is force multiplied by perpendicular distance is also 0 N·m

c) To find the expression for the tension force, T we find the sum of the moment forces about the pin as follows

Sum of moments about p is given as follows

∑M = 0 gives;

T·sin(θ) × L= M×L/2×g

Therefore torque due to tension is given by the following expression

Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) Plugging in the values in the torque due to tension equation, we have;

3\times Tsin60 = \frac{1975\times 3\times 9.81}{2} = 29062.125

Therefore, we make the tension force, T the subject of the formula hence

T= \frac{29062.125}{3 \times sin(60)} = 11186.02 N

8 0
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