Write the equation of the line perpendicular to 2x - 6y = 12 that passes through the point (-3,0).

Mathematics

2 answers:

Trava [24]2 years ago

7 0

Answer:

y = -3x -9

Step-by-step explanation:

slope = 1/3

perpendicular slope = -3

y = mx + b

0 = -3(-3) + b

-9 = b

y = -3x -9

Alex_Xolod [135]2 years ago

4 0

Answer:

y = -3x-9

Step-by-step explanation:

2x - 6y = 12

Solving for y we get

-6y = -2x+12

y = 1/3x -2

The slope is 1/3

Perpendicular lines have slopes that multiply to -1

m * 1/3 = -1

Multiply each side by 3

m * 1/3 * 3 = -1 *3

m = -3

The perpendicular line has a slope of -3

Using the slope intercept form

y = mx+b

y = -3x +b

And the point (-3,0) is substituted into the equation

0 = -3(-3) +b

0 = 9+b

B = -9

y = -3x-9

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