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3 years ago

F(x) = 600x +1200 where x is number of cars sold give the domain and range

Mathematics

1 answer:

uysha [10]3 years ago

7 0

Answer: Domain: (1,+inf) range (1800,inf)

Step-by-step explanation:

assuming that he cant sell negative cars or 0 cars this is the domain and range

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A rectangle's width is twice as long as its length. If the perimeter is 36 in., what is the length?

Bumek [7]

Okay here:

Let L be the length and W the width of the rectangle.

1. w=2•L
2. 2L+2W=36

Substitute eq. 1 into eq. 2,

2L+2•(2•L)=36

2L+4L=36

6L=36

L=9

Not done yet, then from eq. 1,

W=2•L
W=2•9
W=18 <------- Your answer. :)

6 0

3 years ago

Answer with figure if needed.random answer will be reported.

max2010maxim [7]

10m/s

32m/s

83m/s

None of these

Answer :

Solution :

At any instant x2+y2=52

Differentiating w.r.t. time 2xxdt+2ydydt=0

Here dxdt=2,dydt=u⇒u=83m/s

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3 years ago

How to round 54.9 two decimal places

slega [8]

Answer:

54.90

Step-by-step explanation:

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3 years ago

Evaluate the series

dalvyx [7]

Answer:

the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

C) 59

Step-by-step explanation:

Recall that;

$\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\$

Therefore, we can evaluate the series;

$\sum_{k=1}^{6}(25-k^2)$

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

$\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\$

So, the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

6 0

3 years ago

Need help with this math that I don’t know

denis23 [38]

Answer:

$129.00

Step-by-step explanation:

First, we find out the area of the window

(2+6)/2 =4

4*1.5= 6 ft ^2

6*21.5= $129.00

6 0

2 years ago

Read 2 more answers