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JulsSmile [24]
3 years ago
15

8 squared by 6 ÷ 4 squared by 3 =

Mathematics
2 answers:
loris [4]3 years ago
3 0

8^6 ÷ 4^3

8^6 = 262,144

4^3 = 64

So, 262,144 ÷ 64 = 4,096.

Done!

rewona [7]3 years ago
3 0

Answer:

2^12 = 4096

Step-by-step explanation:

Assuming that the problem is:

8^(6) / 4^(3)

1. Convert all numbers to the same base

In other words, rewrite the problem such that all the bases (the numbers under the exponent) are the same.

8 can be rewritten as 2^3

4 can be rewritten as 2^2

Hence the problem is:

((2^(3))^(6)) / ((2^(2))^(3))

2. Combine the exponents on the numerator and denominator

((2^(3))^(6)) / ((2^(2))^(3))

Simplify, remember an exponent to the power of another exponent is the same as multiplying the two exponents, applying this:

(2^(18)) / (2^(6))

3. Simplify the fraction and solve

(2^(18)) / (2^(6))

Dividing two exponents, with the same base is the same as subtracting the exponents, hence:

(2^(12))

= 4096

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Rectangle ABCD was dilated to create rectangle A'B'C'D. Triangle A B C D is dilated to form triangle A prime B prime C prime D.
Julli [10]

Answer:

AB = 6

Step-by-step explanation:

Given

BC = 3.8

A'B' = 15

B'C' = 9.5

Required

Determine the length of AB

Because A'B'C'D is a dilation of ABCD, then the following relationship must exist:

A'B' : AB = B'C' : BC

Substitute values for A'B', B'C' and BC

15 : AB = 9.5 : 3.8

Express the ratio as fractions:

\frac{AB}{15} = \frac{3.8}{9.5}

Multiply through by 14

15 * \frac{AB}{15} = \frac{3.8}{9.5} * 15

AB = \frac{3.8}{9.5} * 15

AB = \frac{3.8* 15}{9.5}

AB = \frac{57}{9.5}

AB = 6

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Step-by-step explanation:

x + 37 + 53 = 180

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The top and bottom margins of a poster are 8 cm and the side margins are each 6 cm. If the area of printed material on the poste
hammer [34]

Answer:

Dimensions of the poster

Width  29.10 cm

Height 38.80 cm

A(min) = 1129.08 cm²

Step-by-step explanation:

Printed area = 390 cm² = Ap

Lets call x and y dimensions of printed area

x   width

y   height

Then Ap = x*y    and

y = Ap/x    ⇒    y = 390/x

Then   total area of the poster is:

A(t)  = ( x  + 12 ) * ( y + 16 )         and   y = 390/x

A as a function of x

A(x) = ( x  + 12 ) * ( 390/x + 16 )   ⇒  A(x) = 390 + 16x + 4680/x + 192

A(x) = 582 + 16x + 4680/x     (1)

Taking derivatives

A´(x) =  16 - (4680/x²)         ⇒ A´(x)  =  0

[ 16x² -4680] /x² = 0     16x²- 4680 = 0    ⇒     x² = 4680/16

x = 17.10 cm        and    y = 390/x      y = 390/17.10      y = 22.80 cm

A(t) = ( 17.10 + 12 ) * ( 22.80 + 16 )

A(t) = 29.10 * 38.80

A(t) = 1129.08 cm²

If we substitute  in equation (1) the value of x  ( 17.10) we see A(x) > 0

Then there is a minimun at the point x = 17.10

4 0
3 years ago
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