How would we show you that
Given:
Consider the below figure attached with this question.
∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°
To find:
The measure of ∠EFH.
Solution:
From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,



Isolate variable terms.


Divide both sides by 13.


The value of x is 4.




Therefore, the measure of ∠EFH is 21°.
If X is between P and Q, then PQ is the whole line segment and XQ and XP are line segments that add up to PQ. Therefore, you can make an equation where XQ and XP add up to PQ.
XQ + XP = PQ
(3k) + (7k - 2) = 6k + 18
Combine like terms.
10k - 2 = 6k + 18
Add 2 to both sides.
10k = 6k + 20
Subtract 6k from both sides.
4k = 20
Divide both sides by 4.
k = 5
Plug 5 for k into XP.
XP = 7(5) - 2 ⇒ 35 - 2
XP = 33
Answer:
x=0
x=10
x=24
Step-by-step explanation:
f(x) = -.05x^2 + x +6
The initial value is 6 ( Let x=0 and f(0) = 6)
f(x) = -.05( x^2 -20 x -120)
I plotted the equation and maximum is at x=10 and the zero is at x=25
Answer:

Step-by-step explanation:
Equation:

Distribute:

Combine like terms:

Hope this helps plz hit the crown :D