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2 years ago

What is the minimum angle of rotation (in degrees) that will carry the star onto itself?

Mathematics

2 answers:

zloy xaker [14]2 years ago

3 0

Answer:

When you rotate the regular pentagon \begin{align*}72^\circ\end{align*} about its center, it will look exactly the same. This is because the regular pentagon has rotation symmetry, and \begin{align*}72^\circ\end{align*} is the minimum number of degrees you can rotate the pentagon in order to carry it onto itself.

Step-by-step explanation:

Lisa [10]2 years ago

3 0

\begin{align*}72^\circ\end{align*} is the minimum number of degrees

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Find S16 for 1 + 7 + 13 + 19 +

amm1812

$S_n=\dfrac{a_1+a_n}{2}\cdot n\\n=16\\a_1=1\\a_{16}=?\\\\a_n=a_1+(n-1)\cdot d\\d=6\\a_{16}=1+(16-1)\cdot6=1+90=91\\\\S_{16}=\dfrac{1+91}{2}\cdot6=46\cdot6=276$

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3 years ago

The drama club was selecting which carnival booths to sponsor at the fall carnival from a list of nine. How many different ways

denis-greek [22]

Answer:

Option B

Step-by-step explanation:

Here we have to apply " combination and permutation. " It is given that the drama club had to choose three booths from a selection of 9, considering the possible ways to choose so. This is a perfect example of combination. In nCr, n corresponds to 9, respectively r corresponds to 3.

$\mathrm{n\:choose\:r},\\nCr=\frac{n!}{r!\left(n-r\right)!},\\\\\frac{9!}{3!\left(9-3\right)!} =\\\frac{9!}{3!\cdot \:6!} =\\\\\frac{9\cdot \:8\cdot \:7}{3!} =\\\frac{504}{6} =\\\\84\\\\Solution = Option B$

Hope that helps!

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2 years ago

Janie earned $15.50 at her part time job on Saturday

mina [271]

Answer:48 dollars

Step-by-step explanation:Just add 32.50 and 15.50 to get 48

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2 years ago

Read 2 more answers

If the m angle 2 = 113 what is the angle 6

dmitriy555 [2]

m < 6 = m < 2 because they are corresponding angles

So m < 6 = 113 degrees answer

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2 years ago

The number of flaws per square yard in a type of carpet material varies with mean 1.4 flaws per square yard and standard deviati

oksian1 [2.3K]

According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:
$\frac{\sigma}{ \sqrt{n} }=\frac{1.2}{ \sqrt{178} }=0.09$
The z-score for 1.5 flaws per square yard is:
$z=\frac{1.5-1.4}{0.09}=1.11$
The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.

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3 years ago