We will use the followin property of logarithms:
![log(a^b) = b log(a)](https://tex.z-dn.net/?f=%20log%28a%5Eb%29%20%3D%20b%20log%28a%29%20)
So, we have
![log(3^2) = 2 log(3) = 0.631](https://tex.z-dn.net/?f=%20log%283%5E2%29%20%3D%202%20log%283%29%20%3D%200.631%20)
If you multiply both sides by 4, you get
![8log(3) = log(3^8) = 2.524](https://tex.z-dn.net/?f=%208log%283%29%20%3D%20log%283%5E8%29%20%3D%202.524%20)
Answer:
child's ticket = 4.75 adult ticket=10.75.
Step-by-step explanation:
The cost of an adult ticket is 6 more than that of a child ticket, so will be denoted by c+6. Now, we are told that the cost of four child tickets and two adult tickets is 40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
Therefore the cost of a child's ticket (c) is 4.75 and the cost of an adult ticket (c+6) is 10.75.
Can u take a picture please?
Answer:
Step-by-step explanation:
a) sub in 600 for 6
600-25/40 =14.375
b) switch x and y
x=y-25/40
Solve for y
40x=y-25
y=40x+25
c)Plug in 2.5 for z(x)
2.5= x-25/40
100=x-25
x=125