Answer:
![z = \frac{X -\mu}{\sigma}](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7BX%20-%5Cmu%7D%7B%5Csigma%7D)
And we can solve for the value of X like this:
![X = \mu + z*\sigma](https://tex.z-dn.net/?f=%20X%20%3D%20%5Cmu%20%2B%20z%2A%5Csigma)
And since we know that z=2 we can replace and we got:
![X = 49 +2*20.7= 90.4 \approx 90](https://tex.z-dn.net/?f=%20X%20%3D%2049%20%2B2%2A20.7%3D%2090.4%20%5Capprox%2090)
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the scores of a population, and for this case we can assume the distribution for X is given by:
Where
and
And for this case the z score is given by:
![z = \frac{X -\mu}{\sigma}](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7BX%20-%5Cmu%7D%7B%5Csigma%7D)
And we can solve for the value of X like this:
![X = \mu + z*\sigma](https://tex.z-dn.net/?f=%20X%20%3D%20%5Cmu%20%2B%20z%2A%5Csigma)
And since we know that z=2 we can replace and we got:
![X = 49 +2*20.7= 90.4 \approx 90](https://tex.z-dn.net/?f=%20X%20%3D%2049%20%2B2%2A20.7%3D%2090.4%20%5Capprox%2090)
Answer:
Factor the numerator and denominator and cancel the common factors.
1
Step-by-step explanation:
Hope this helps! Have a nice day!
11 nCr 3 plugged in a calculator will equal 165 Combinations/Positions
The horizontal asymptote of the function is the minimum number of deer in the area.
- The equation of horizontal asymptote is:
![\mathbf{y = 40}](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%2040%7D)
- The horizontal asymptote means that, the number of deer will never be less than 40
The equation is given as:
![\mathbf{f(x) = \frac{40 + 2x}{1 + 0.05x}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%28x%29%20%3D%20%5Cfrac%7B40%20%2B%202x%7D%7B1%20%2B%200.05x%7D%7D)
Expand the numerator
![\mathbf{f(x) = \frac{40(1 + 0.05x)}{1 + 0.05x}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%28x%29%20%3D%20%5Cfrac%7B40%281%20%2B%200.05x%29%7D%7B1%20%2B%200.05x%7D%7D)
Cancel out the common factor
![\mathbf{f(x) = 40}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%28x%29%20%3D%2040%7D)
Hence, the equation of horizontal asymptote is:
![\mathbf{y = 40}](https://tex.z-dn.net/?f=%5Cmathbf%7By%20%3D%2040%7D)
The horizontal asymptote means that, the number of deer will never be less than 40
Read more about horizontal asymptotes at:
brainly.com/question/4084552