Answer:
The equation of line with given points and perpendicular to y-axis is
y = - 7
Step-by-step explanation:
Given as :
The given points as ( - 10 , - 7)
The equation of line is Y = mX + c
So The line will satisfy given points
Or, - 7 = m ( -10 ) + c
Now This line is perpendicular to y- axis
∴ The slop of line perpendicular to y axis is 0
So, - 7= 0 + c
or, c = - 7
∴ Equation of line is y = 0 + c
Or, y = - 7
Hence The equation of line with given points and perpendicular to y-axis is y = - 7 Answer
Answer:
Answer – A and B
A. It is a parabola
B. It is in quadrants I and II
The most simple quadratic function is y = x^2. The graph drawn for this function, y = x^2) is known as the graph of the quadratic parent function OR the parent function for parabolas. This graph has some few characteristics:
- It is the simplest parabola (Generally, the graph of any quadratic function is a parabola).
- It passes through the origin (0,0).
- It is contained in Quadrants I and II.
hope this helps!
Answer:
5-(-3y+3z)-3(-5z-y) = 6y+12z+5
Step-by-step explanation:
5−(−3y+3z)−3(−5z−y)
Distribute:
=5+3y+−3z+(−3)(−5z)+(−3)(−y)
=5+3y+−3z+15z+3y
Combine Like Terms:
=5+3y+−3z+15z+3y
=(3y+3y)+(−3z+15z)+(5)
=6y+12z+5
0.7 is the answer. Hope this helps
