Taylor organizes and manages all his files and folders logically. How does this activity help Taylor in his daily work environme
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Answer:
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Explanation:
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Answer:
correct option is B. about 30 years
Explanation:
given data
real per capita GDP west = $10,000
annual growth rate = 2.33%
real per capita GDP east = $2,500
annual growth rate = 7%
to find out
How many years will it take for East to catch up GDP of West
solution
we know here that future value is equal to real GDP of west after time will be
future value = real per capita GDP west ×
future value = 10000 × .....1
and
future value = real per capita GDP east ×
future value = 2500 × .....2
compare equation 1 and 2
10000 × = 2500 ×
4 =
t = about 30 years
so correct option is B. about 30 years
Given:
Principal, P = 26500
term=5 years
Monthly payment, A = 695
Question: Find interest rate
Solution:
Unless there is a table available, there is no explicit formula to calculate interest. However, the interest rate can be solved for using the formula to calculate the monthly payment, as follows.
Substituting
P=26500
i=monthly interest rate to be found
A=monthly payment=695
n=5*12=60 months
Rearrange to give successive estimates of i by
I(i)=(695/26500)*((1+i)^60-1)/(1+i)^60
Try initial estimate of i=0.02 (2% per month)
I(0.02)=0.0182
I(0.0182)=0.01736
I(0.01736)=0.01689
....
Eventually we get the value to stabilize at i=0.016265, or
Monthly interest = 1.6265% (to four decimal places)
Principal, P = 26500
term=5 years
Monthly payment, A = 695
Question: Find interest rate
Solution:
Unless there is a table available, there is no explicit formula to calculate interest. However, the interest rate can be solved for using the formula to calculate the monthly payment, as follows.
Substituting
P=26500
i=monthly interest rate to be found
A=monthly payment=695
n=5*12=60 months
Rearrange to give successive estimates of i by
I(i)=(695/26500)*((1+i)^60-1)/(1+i)^60
Try initial estimate of i=0.02 (2% per month)
I(0.02)=0.0182
I(0.0182)=0.01736
I(0.01736)=0.01689
....
Eventually we get the value to stabilize at i=0.016265, or
Monthly interest = 1.6265% (to four decimal places)