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Ivenika [448]
3 years ago
14

ABCDE is a regular pentagon. The apothem is 9.7 cm, and AB = 14.1 cm. Calculate the area of the pentagon. Round the answer to th

e nearest tenth.
Mathematics
1 answer:
devlian [24]3 years ago
8 0
        ABCDE is a regular pentagon which consists of 5 equal triangles.
Area of the pentagon ABCDE:
        A = 5 * 1.41 * 9.7 / 2 = 683.85 / 2 = 341.925 ≈ 341.9 cm²
       Answer: The area of the pentagon ABCDE is 341.9 cm².
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The three angles of a triangle are in the ratio 5:4:1. Find all the angles of the triangle.
solniwko [45]

Answer:

Step-by-step explanation:

let the first angle be 5x

second be 4x

and third be 1x

as we know that by adding all the sides of triangle we get 180°

therefore  ,

5x+4x+1x=180°

10x=180°

hence ,  

x=18°

first angle - 18*5 = 90°

second angle - 18*4=72°

third angle - 18°

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6 0
3 years ago
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Ludmilka [50]

Answer:

7x-7=y

Step-by-step explanation:

5x+7y=10

5x-10=10-7y-10

5x-10=-7y

(1/7)5x-10=7y(1/7)

5x/35-10/70=y

7x-7=y

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6 0
3 years ago
Priya bought these items at the grocery store. Find each unit price. A. 12 eggs for $3. How much is the cost per egg? B. 3 pound
Ratling [72]

Answer: A. Cost per egg = $4 .

B. Cost per pound = $ 2.5

C. Cost per roll = $ 0.5

D. Cost per apple = $0.35

Step-by-step explanation:

Formula: cost per item = (total cost) ÷ (number of items)

A. 12 eggs for $3.

Cost per egg = $ (12÷3) = $4

So, Cost per egg = $4 .

B. 3 pounds of peanuts for $7.50

Cost per pound of peanuts = $ (7.50 ÷ 3)= $ 2.5

So, Cost per pound = $ 2.5

C. 4 rolls of toilet paper for $2.

Cost per roll = $ (2 ÷4 ) = $ 0.5

So, Cost per roll = $ 0.5

D.  10 apples for $3.50.

Cost per apple = $ (3.50 ÷ 10)= $ 0.35

So,  Cost per apple = $0.35

4 0
3 years ago
PLEASE HELP!
Marrrta [24]

Answer:

15.6 feet

Step-by-step explanation:

3 0
3 years ago
Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
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