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Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
As you bring all the non-variable numbers over to the right side, it becomes 384 which you then will divide the 32 in x which gives us 12. so x=12
Answer:
And for this case the margin of error would be:
If the level of confidence increase we can conclude that the value of would increase and the the confidence interval would be wider, since the margin of error increase.
c. Increase; wider
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
Let's assume that we have a parameter of interest and we want to estimate the value of p with and in general the confidence interval if the distribution of p is normal is given by:
And for this case the margin of error would be:
If the level of confidence increase we can conclude that the value of would increase and the the confidence interval would be wider, since the margin of error increase.
c. Increase; wider
<h3>
Answer: C) 2/7</h3>
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Explanation:
Initially there are 15+18+12 = 45 marbles total. He selects 3 marbles (2 reds, 1 blue).
Assuming he doesn't put the three marbles back, this means there are now 45-3 = 42 marbles overall. The yellow count hasn't changed since the first three marbles do not involve yellow. We have 12 yellow out of 42 which leads to the fraction 12/42 to represent the probability of getting yellow.
Reduce 12/42 to get 2/7. You divide both parts by the GCF 6.
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Side note: if he did put the marbles back, then the probability of getting yellow would be 12/45 = 4/15